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TEST GRAPH AND WRITE QUADRATIC FUNCTIONS 9

Total questions: 15

Worksheet time: 4hrs 45mins

Name
Class
Date
1.
The equation for this graph is...
a)
y = x2
b)
y = -x- 1
c)
y = x2  - 1
d)
y = -x2
2.

Which of the following graphs could be y = 5x2 + 1?

a)
b)
c)
d)
3.

What is the equation of this graph?

a)

y = - x2

b)

y = - x2 - 3

c)

y = - x2 + 3

d)

y = x2 + 3

4.

Write the equation in standard form of the parabola passing through the points (1, -4), (2, -3), (3, -4).

a)

y=x27x+5y=x^2-7x+5

b)

y=x2+4x7y=-x^2+4x-7

c)

y=x25x2y=x^2-5x-2

d)

y=x2+3x8y=-x^2+3x-8

5.
The axis of symmetry is a line that goes through the...
a)
y-intercept
b)
any random point
c)
vertex
d)
 x-axis or y-axis
6.
The equation for the axis of symmetry for this parabola is...
a)
x = 0
b)
x = -2
c)
y = -2
d)
x = 2
7.
Where is the axis of symmetry for this parabola?
a)
x = −1
b)
x = 0
c)
y = 3
d)
x = −3
8.

A parabola has a vertex at (-6,5).

Where is the axis of symmetry?

a)

y = -5

b)

x = 6

c)

x = -6

d)

y = 10

9.

What is the axis of symmetry for the equation f(x) = -9x2 - 72x + 23

a)

x = -4

b)

x = 8

c)

x = 4

d)

x = -9

10.

Which graph represents the following equation: y=x22x+3y=-x^2-2x+3  

a)
b)
c)
d)
11.

A model for a company's revenue is

 R=15p2+600p+12000R=-15p^2+600p+12000  where p is the price in dollars of the company's product. What price will maximize revenue? Find the maximum revenue.

a)

A price of $13,500 will maximize revenue. The maximum revenue is $10.

b)

A price of $12 will maximize revenue. The maximum revenue is $15,500.

c)

A price of $10 will maximize revenue. The maximum revenue is $20,500.

d)

A price of $20 will maximize revenue. The maximum revenue is $18,000.

12.

The number of weekends get-away packages a hotel can sell can be modeled by -0.15p +60, where p is the price of a get-away package. The revenue is the product of the price and the number of packages sold. What price will maximize revenue? Find the maximum revenue.

a)

A price of 250 will maximize revenue. The maximum revenue is $5,625.

b)

A price of $200 will maximize revenue. The maximum revenue is $6,000.

c)

A price of $5,625 will maximize revenue. The maximum revenue is $250.

d)

A price of $350 will maximize revenue. The maximum revenue is $7,625.

13.

The graph of y = x2 + 1 could be?

a)
b)
c)
d)
14.
Find the vertex of 
f(x) = -x- 4x + 12
a)
(-2, 16)
b)
(2, 0)
c)
(2, 4)
d)
(-2, 4)
15.

What is the equation of this graph?

a)

y=2x2+8x9y=2x^2+8x-9

b)

y=2x2+8x+9y=2x^2+8x+9

c)

y=x2+8x+9y=x^2+8x+9

d)

y=x2+4x+9y=x^2+4x+9