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Limiting reactants & Percent yield

Total questions: 11

Worksheet time: 55mins

Name
Class
Date
1.

Zn + 2HCl <=> ZnCl2 + H2


65g of Zinc reacts with 79g of Hydrochloric Acid to produce Zinc Chloride and Hydrogen gas. What is the limiting reactant?

a)

Hydrogen gas

b)

Hydrochloric Acid

c)

Zinc chloride

d)

Zinc

2.

Na2CO3 + 2HCl <=> 2NaCl + CO2 + H2O


87g of Sodium bicarbonate (Na2CO3) reacts with 120g of hydrochloric acid (HCl) to produce sodium chloride, carbon dioxide and water. What is the limiting reactant?

a)

Sodium bicarbonate

b)

Hydrochloric acid

c)

Water

d)

Sodium chloride

3.

SiCl4 + 4H2O <=> H4SiO4 + 4HCl


40g of Silicon Tetrachloride (SiCl4) reacts with 22g of Water to produce Silicic Acid and Hydrochloric Acid (HCl). What is the excessive reactant?

a)

Water

b)

Hydrochloric Acid

c)

Silicic Acid

d)

Silicon Tetrachloride

4.

2C7H6O2 + 15O2 <=> 14CO2 + 6H2O


23.0g of oxygen gas reacts with 42.0g of benzoic acid (C7H6O2) to produce carbon dioxide and water. What is the limiting reactant?

a)

Carbon dioxide

b)

Oxygen gas

c)

Benzoic acid

d)

Water

5.

4Si2H3 + 11O2 <=> 8SiO2 + 6H2O


30g of Disilicon Trihydride (Si2H3) reacts with 50g Oxygen gas to produce Silicon Dioxide (SiO2) and water. What is the excessive reactant?

a)

Water

b)

Disilicon Trihydride

c)

Silicon Dioxide

d)

Oxygen gas

6.

What is the equation to calculate percent yield?

a)

(Actual yield / Theoretical yield) x 100% = Percent yield

b)

(Theoretical yield / Actual yield) x 100% = Percent yield

c)

Mass (1 Mole / Molar mass) x 100% = Percent yield

d)

Mass x Speed x 100% = Percent yield

7.

Na2CO3 + 2HCl <=> 2NaCl + CO2 + H2O


Billy performed the preceding chemical reaction using 76g of Na2CO3 and produced 48g of NaCl. This did not match his theoretical yield. What was Billy's percent yield?

a)

50%

b)

22%

c)

48%

d)

57%

8.

Zn + 2HCl <=> ZnCl2 + H2


Billi performs the preceding reaction using 50g of Zinc and produced 10g of Zinc chloride. What is Billi's percent yield?

a)

42%

b)

36%

c)

24%

d)

30%

9.

2C7H6O2 + 15O2 <=> 14CO2 + 6H2O


Philly reacted 120g of Benzoic acid with a surplus of Oxygen gas. If the reaction produced 60g of Carbon dioxide what was Philly's percent yield?

a)

20%

b)

50%

c)

45%

d)

78%

10.

SiCl4 + 4H2O <=> H4SiO4 + 4HCl


Molly reacted 40g of Silicon Tetrachloride (SiCl4) with a surplus of Water to produce Silicic Acid (H4SiO4). Molly collected 60g of Silicic Acid, what was her percent yield?

a)

180%

b)

150%

c)

256%

d)

300%

11.

4Si2H3 + 11O2 <=> 8SiO2 + 6H2O


Millie reacts 30g of Disilicon Trihydride (Si2H3) with an excess of Oxygen gas and produces 70g of Silicon Dioxide (SiO2). This doesn't match her calculations however. What is Millie's percent yield?

a)

100%

b)

87%

c)

49%

d)

115%