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Dimensional Analysis Setup Only

Total questions: 8

Worksheet time: 5mins

Name
Class
Date
1.

What unit should be in the denominator (bottom) of the conversion factor?

a)

yards

b)

leagues

c)

feet

d)

fathoms

2.

What unit should be in the numerator (top) of the conversion factor?

a)

yards

b)

leagues

c)

feet

d)

fathoms

3.
What conversion factor would you use to solve this problem?
a)
2.20 lbs / 1 kg
b)
1 kg / 2.20 lbs
c)
0.002 lbs / 1 g
d)
1 g / 0.002 lbs
4.

Which conversion factor would be needed?

a)
b)
c)
d)
5.

Which conversion factor would be needed?

a)
b)
c)
d)
6.

Which of the following shows the correct work to convert 25.0 inches to cm? (Relationship: 1 inch = 2.54 cm)

a)

 25.0 in  x  2.54 cm1 in=25.0\ in\ \ x\ \ \frac{2.54\ cm}{1\ in}=  

b)

 2.54 cm x 1 in25.0 cm=2.54\ cm\ x\ \frac{1\ in}{25.0\ cm}=  

c)

 1 in x 2.54 cm25 in=1\ in\ x\ \frac{2.54\ cm}{25\ in}=  

d)

 25 in x 1 in2.54 cm=25\ in\ x\ \frac{1\ in}{2.54\ cm}=  

7.

Which of the following choices shows the correct setup to find out how many yards are in 575 inches?

a)

 575 yd  x  3 ft1 yd x 12 in1 ft=575\ yd\ \ x\ \ \frac{3\ ft}{1\ yd}\ x\ \frac{12\ in}{1\ ft}= 

b)

 575 in  x  1 ft12 in x 1 yd3 ft=575\ in\ \ x\ \ \frac{1\ ft}{12\ in}\ x\ \frac{1\ yd}{3\ ft}= 

c)

 575 in  x  12 in1 ft x  3 ft1 yd = 575\ in\ \ x\ \ \frac{12\ in}{1\ ft}\ x\ \ \frac{3\ ft}{1\ yd}\ =\  

d)

 575 in  x 1 ft12 in x  3 ft1 yd=575\ in\ \ x\ \frac{1\ ft}{12\ in}\ x\ \ \frac{3\ ft}{1\ yd}= 

8.

If 1 mile = 1.61 km and 1000m = 1km, what is the correct work to solve how many miles are in 9,999 meters?

a)

 9,999 m x 1.61 km1 m x 1 mi1000 m=9,999\ m\ x\ \frac{1.61\ km}{1\ m}\ x\ \frac{1\ mi}{1000\ m}=  

b)

 9,999 m x 1 km1000 mx 1 mi1.61 km=9,999\ m\ x\ \frac{1\ km}{1000\ m}x\ \frac{1\ mi}{1.61\ km}=  

c)

 1.61 km x 1 mi1000 kmx 9999 m1 mi=1.61\ km\ x\ \frac{1\ mi}{1000\ km}x\ \frac{9999\ m}{1\ mi}=  

d)

 9,999 m x 1.61 km1 mi = 9,999\ m\ x\ \frac{1.61\ km}{1\ mi}\ =\