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WorksheetsCOMPLETING THE SQUARE
Total questions: 18
Worksheet time: 5hrs 30mins
Solve by completing the square.
x2−8x−20=0
x={−2, 10}
x={−10, 2}
x={−20, −8}
x={8, 20}
Solve by completing the square.
x2−12x+20=0
x={2, 10}
x={−10, −2}
x={−12, 20}
x={12, 20}
Solve by completing the square.
x2−6x−27=0
x={−9, −3}
x={−3, 9}
x={−9, 3}
x={3, 9}
Solve by completing the square.
x2−14x−15=0
x={1, 15}
x={−15, −1}
x={−15, 1}
x={−1, 15}
Solve by completing the square.
x2−6x−59=0
x={±217+3}
x={±172+3}
x={±217−3}
x={±172−3}
x2 +12x = 5
y= x2-2x-5
into vertex form.
Determine the vertex of the parabola y=5(x-2)2–7
(5, -7)
(-2, -7)
(2, -7)
(-7, -2)
Solve the equation by completing the square.
−x2−2x+5=0x=−1±2i
x=1±2i
x=−2±i
x=−1±i2
Solve the equation by completing the square.
x2+6x+22=0x=3±i13
x=−3±3i10
x=3±3i10
x=−3±i13
Write in vertex form
y=−x2+4x−1y=−(x−2)2+3
y=(x+2)2+3
y=−(x−2)2−3
y=−(x+2)2−3
Write in vertex form
y=2x2−8x+1y=2(x+2)2−7
y=2(x−2)2+7
y=2(x−2)2−7
y=2(x−7)2−2
The profit P from handmade sweaters depends on the price s at which each sweater is sold. The function
P=−s2+120s−2000 models the monthly profit from sweaters for one custom tailor. What is the maximum monthly profit, in dollars, determined by this model?Hint: Write the function in vertex form.
A price of $60 per sweater gives a maximum monthly profit of $1600.
A price of $70 per sweater gives a maximum monthly profit of $1800.
A price of $50 per sweater gives a maximum monthly profit of $1500.
A price of $80 per sweater gives a maximum monthly profit of $2100.
An electronic company has a new line of headphones with bluetooth. Their research suggests that the daily sales s for the new product can be modeled by
s=−p2+120p+1400, where p is the price of each unit. What price gives maximum daily sales and what are the maximum daily sales?A price of $70 per headphone gives a maximum daily sales of $7000.
A price of $60 per headphone gives a maximum daily sales of $4500.
A price of $60 per headphone gives a maximum daily sales of $5000.
A price of $70 per headphone gives a maximum daily sales of $5500.
The height of a punted football can be modeled with the quadratic function
h=−0.01x2+1.18x+2. the horizontal distance in feet from the point of impact with the kicker's foot is x, and h is the height of the football in feet.Find the vertex of the graph by completing the square.
(58, 35.71)
(59, 36.81)
(59, 35.81)
(58, 36.81)
The height of a punted football can be modeled with the quadratic function
h=−0.01x2+1.18x+2. the horizontal distance in feet from the point of impact with the kicker's foot is x, and h is the height of the football in feet.Find the vertex of the graph by completing the square. The nearest defensive player is 5 ft. horizontally from the point of impact. How high must the player reach to block the punt?7.65 ft
7.55 ft
8.65 ft
7.45 ft
