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WorksheetsT2-SBQ2-G11 ADV-CAI
Total questions: 25
Worksheet time: 45mins
When CH3OH is dissolved in water, how many particles are in solution for each unit?
1
3
4
6
At the same concentration, which salt will have the largest effect on the freezing point?
C2H4O2
H2S
LiBr
CaF2
Find the boiling point of a solution containing 15.0 g sucrose (molar mass = 342.3g/mol), in 100g of water. (Kb = 0.512 oC/m)
100.2
99.8
0.2
-0.2
When 26.0 g of NaCl, are dissolved in 0.5 kg of water, what is the freezing point of this solution? (Kf = 1.86 oC/m)
-3.3
103.3
-1.7
-0.8
A solution contains 15.5 g of a nonelectrolyte and 200 g of water. The water freezes at -4.5° C and Kf = 1.86° C/m. What is the molar mass of the nonelectrolyte?
18g/mol
32g/mol
16g/mol
46g/mol
Which of the following statements is TRUE?
Ionic solutes affect colligative properties more than covalently bonded solutes because they produce more moles of solute in solution.
Ionic solutes affect colligative properties less than covalently bonded solutes because they produce less moles of solute in solution.
Covalent solutes affect colligative properties more than ionically bonded solutes because they produce more moles of solute in solution.
Covalent solutes affect colligative properties less than ionically bonded solutes because they produce more moles of solute in solution.
Which type of solute affects colligative properties like freezing point and boiling point the LEAST?
ionic because they dissociate into at least 2 solute particles
ionic because they are non-dissociative and always pull into one molecule at a time
covalent because they dissociate into at least 2 solute particles
covalent because they are non-dissociative and always pull into one molecule at a time
Rank the following solutes from least to greatest effect on freezing point:
KI, CH3OH, Li3PO4, CaCl2
KI, CH3OH, Li3PO4, CaCl2
Li3PO4, CaCl2, KI, CH3OH
Li3PO4, CH3OH, CaCl2, KI
CH3OH, KI, CaCl2, Li3PO4
Examine the models below. Assuming the same concentration, which would affect colligative properties more?
beaker A
beaker B
What gas is formed when ammonium chloride is warmed with aqueous sodium hydroxide?
Ammonia
Chlorine
Oxygen
Hydrogen
Aqueous sodium hydroxide reacts with a metal ion producing a green coloured precipitate. What is the ion present?
Al3+
Cu2+
Fe2+
Fe3+
After acidification with dilute nitric acid, a colourless solution of X reacts with aqueous silver nitrate to give a white precipitate. What could X be?
Calcium iodide
Copper(II) chloride
Lead(II) iodide
Sodium chloride
A salt is dissolved in water. The results of two separate tests on it are shown in the table.
- white precipitate which dissolved when excess aqueous ammonia is added.
- white precipitate is formed when dilute nitric acid and aqueous barium nitrate is added to the salt solution. What is the salt?
Aluminium chloride
Aluminium sulfate
Zinc chloride
Zinc sulfate
Which cation gives a lilac flame colour?
K+
Na+
Ca+2
Cu+2
Fe+2
Which cation gives a blue precipitate with NaOH?
Fe+2
Al+3
Ca+2
Cu+2
Fe+3
A beaker contains a solution (y) , it reacts with HCl forming a gas turbid lime water , and by adding Silver nitrate solution to it , yellow ppt is formed ( then the anions in the solution are .. )
CO32- , I-
Cl- , CO32-
Br- , SO42-
Ca2+ , I-
0.1 M NaCl and 0.1 glucose(C6H12O6) has the same effect on the boiling point of water
True
False
A students is asked to investigate the nature of a purple colored salt solution and the student claims that MnO4 - ions are present. Do you agree with the students' claim?
Yes, I agree
NO, I do not agree
A student carried out a qualitative analysis experiment to investigate two solutions (X and Y). Use the information in the table below to identify the nature of the two solutions
X= FeI2. and Y= CuCl2
X= FeI3. and Y= CuCl2
X= FeI2. and Y= Cul2
X= CuI2. and Y= CuCl2
Which of the following solutions is green?
A
B
C
D
Which of the following depend(s) on the number of solute particles dissolved in solution?
I. Vapor pressure lowering
II.Freezing point depression
III.Boiling point elevation
I only
II and III only
II only
I,II and III
Solubility is considered a colligative property.
True
False
When 11.0 g of CaCl2 dissolves in 45.0 g of water, what is the boiling point of the solution? (Kb = 0.512 oC/m). The formula mass of CaCl2 is 111 amu. Note you need to calculate the boiling point of solution and not the change.
3.4
103.4
101.1
101.4
