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10.5 Solving Trig Equations

Total questions: 12

Worksheet time: 2hrs 0mins

Name
Class
Date
1.

How many solutions does the following equation have on the given interval?

 sinx=12\sin x=\frac{1}{2}  when  0x<2π0\le x<2\pi  

a)

0

b)

1

c)

2

d)

4

2.

How many solutions does the following equation have on the given interval?

 tan2x=3\tan^2x=3  when  0x<2π0\le x<2\pi  

a)

0

b)

1

c)

2

d)

4

3.

 cosx+cos2x=0\cos x+\cos^2x=0  

What method would you use to solve the equation?

a)

greatest common factor

b)

cancel cosines

c)

combine like terms

d)

square roots

4.

Solve cosx+cos2x=0\cos x+\cos^2x=0  on the interval  πx<3π2\pi\le x<\frac{3\pi}{2}  


a)

 π2\frac{\pi}{2}  

b)

 3π2\frac{3\pi}{2} 

c)

 π\pi  

d)

 5π4\frac{5\pi}{4}  

5.

 cot2x2cotx+1=0\cot^2x-2\cot x+1=0  

What method would you use to solve the equation?

a)

square roots

b)

combining like terms

c)

factoring

d)

trig identities

6.

 cot2x2cotx+1=0\cot^2x-2\cot x+1=0  

Solve on the interval  πx<2π\pi\le x<2\pi  

a)

 π4\frac{\pi}{4}  

b)

 3π4\frac{3\pi}{4}  

c)

 5π4\frac{5\pi}{4}  

d)

 7π4\frac{7\pi}{4}  

7.

 2sin2x=22\sin^2x=2  

What method would you use to solve the equation?

a)

square roots

b)

combining like terms

c)

factoring

d)

trig identities

8.

 2sin2x=22\sin^2x=2  

Solve the equation on the interval  0x<2π0\le x<2\pi  

a)

0

b)

 π6\frac{\pi}{6}  

c)

 π2\frac{\pi}{2}  

d)

 3π2\frac{3\pi}{2}  

e)

 π\pi  

9.

 2sinxcosx=02\sin x\cos x=0  

What method would you use to solve the equation?

a)

square roots

b)

combining like terms

c)

factoring

d)

trig identities

10.

 2sinxcosx=02\sin x\cos x=0  

Solve the equation on the given interval  x{all real numbers}x\in\left\{all\ real\ numbers\right\}  

a)

 0+π2n0+\frac{\pi}{2}n  

b)

 0+πn0+\pi n  

c)

 π2+2πn\frac{\pi}{2}+2\pi n  

d)

 0+2πn0+2\pi n  

11.

 2cos2xcosx=12\cos^2x-\cos x=1  

What method would you use to solve the equation?

a)

cry

b)

combining like terms

c)

factoring (move the 1 first)

d)

greatest common factor

12.

 2cos2xcosx=12\cos^2x-\cos x=1  

Solve on the interval  0x<2π0\le x<2\pi  

a)

0

b)

 2π3\frac{2\pi}{3}  

c)

 4π3\frac{4\pi}{3}  

d)

 π\pi  

e)

 π2\frac{\pi}{2}