WorksheetsVCFT: CAT 3 MCQ
Total questions: 10
Worksheet time: 2hrs 40mins
SinA sin B=
21[sin(A+B)+sin(A−B)]
21[sin(A+B)−sin(A−B)]
21[cos(A+B)+cos(A−B)]
21[cos(A−B)−cos(A+B)]
Fs[f(x) cosax] is
21[Fs(A+S)−Fs(A−S)]
21[Fs(A+S)+Fs(A−S)]
21[Fc(A+s)+Fc(A−s)]
21[Fc(A+s)−Fc(A−s)]
The convolution Theorem is
F[af+bg] =aF[s] +bG[s]
F[f⋅g] =F[s] ⋅G[s]
F[af] =∣a∣1F[as]
F[f′(x)] =−isF[s]
The Fourier Sine Transform of
e−5xFs[e−5x]=π2 52+s25
Fs[e−5x]=π2 52+s2s
Fs[e−5x]=π2 a2+s2s
none of the above
Fs(xf(x)) =
dsd Fc[s]
−dsd Fc[s]
dsd Fs[s]
dsd Fs[s]
Convolution operation is commutative
true
false
some times
none
Parsevals identity for Fourier Transform is
∫−∞∞∣f(x)∣2dx=∫−∞∞∣f(s)∣2ds
∫0∞∣f(x)∣2dx=∫0∞∣f(s)∣2ds
∫−∞∞∣f(x)∣dx=∫−∞∞∣f(s)∣ds
∫−∞∞f(x)2dx=∫−∞∞f(s)2ds
∫0∞t2sin2t dt
2π
4π
π
0
The inverse Fourier Transform of F[f(x)] is f(x) =
2π1∫−∞∞ F[s] dx = f(x)
2π1∫−∞∞F[s]eisx ds =f(x)
2π1∫−∞∞F[s] e−isxds =f(x)
2π1∫−∞∞F[s] cossx ds = f(x)
The Fourier cosine Transform of f(x) is Fc[f(x)]=
2π1∫−∞∞f(x) cossx dx = Fc[s]
2π1∫0∞f(x) cossx dx = Fc[s]
π2∫0∞f(x) cossx dx = Fc[s]
2π1∫−∞∞f(x) cossx dx = Fs[s]
