Wayground logo

Free Printable Worksheets

Font size

S
M
L
XL
Worksheets

B.Sc. I Chapter III

Total questions: 10

Worksheet time: 5mins

Name
Class
Date
1.

A parallel beam of white light is incident on a thin film of oil of thickness 2×10−72\times10^{-7}   m. The normally reflected light is observed and it shows the first dark fringe at a certain wavelength. If refractive index of oil is 1.4, ------- the wavelength of colour is absent.

a)

 5600 A05600\ A^0  

b)

 2800 A02800\ A^0  

c)

 1400 A01400\ A^0  

d)

 5800 A05800\ A^0  

2.

The fringes obtained in case of Newton’s rings experiment are ----

a)

localized fringes

b)

of equal thickness

c)

localized and equal thickness

d)

delocalized

3.

A parallel beam of light of wavelength 6000A0 is incident on a thin glass plate of refractive index 1.5. The angle of refraction in the plate is 600. Calculate the minimum thickness of the plate so that it appears completely dark in reflected light.

a)

4000 A0

b)

2000 A0

c)

1000 A0

d)

6000 A0

4.

The fringes observed in case of wedge shaped thin film are ----

a)

equally spaced

b)

of equal thickness

c)

localised

d)

equally spaced, localized and of equal thickness

5.

When a progressive wave gets reflected from the surface of a denser medium, its phase changes by---

a)

900

b)

1800

c)

3600

d)

450

6.

When a ray of light gets reflected from the surface of a denser medium, then additional path difference introduced is ---

a)

λ2\frac{\lambda}{2}

b)

λ4\frac{\lambda}{4}

c)

3λ2\frac{3\lambda}{2}

d)

λ\lambda

7.

The distance between successive Newton’s rings experiment ---- as the order n of the fringes increases.

a)

increases

b)

decreases

c)

remains constant

d)

none of these

8.

In case of Newton’s rings experiment if the ring pattern is formed due to reflected light then the centre of the ring pattern is ----

a)

dark

b)

bright

c)

dark or bright

d)

semi-dark

9.

A beam of monochromatic light of wavelength  5.82×10−75.82\times10^{-7}   m falls normally on a glass wedge, makes fringes with fringe width 0.2 cm, then ----- is the number of fringes per cm of the wedge length.

a)

5 per cm 

b)

10 per cm

c)

2.5 per cm

d)

1 per cm

10.

For maximum of interference the value of path difference is ---

a)

(n+12)λ\left(n+\frac{1}{2}\right)\lambda

b)

(2n+1) λ2\left(2n+1\right)\ \frac{\lambda}{2}

c)

nλ2\frac{n\lambda}{2}

d)

nλn\lambda