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QUIZ:2 CH2 SOLUTION [CONCENTRATION TERMS]

Total questions: 15

Worksheet time: 16mins

Name
Class
Date
1.

HOW MANY TYPE OF SOLUTIONS ARE POSSIBLE BETWEEN SOLUTE AND SOLVENT BY TAKING THREE STATES OF MATTER?

(a)  

2.

Concentration is

a)

the amount of solute in fixed amount of solvent

b)

the amount of solvent in the solute

c)

density

d)

particle size

3.

Which solution is more concentrated?

Solution 1:

500 mL of water

100 g of salt


Solution 2:

500 mL of water

90 g of salt

a)

Solution 1

b)

Solution 2

c)

They have the same concentration

d)

I have no idea

4.

Which solution is more diluted?

Solution 1:

1000 mL of water

60g of salt


Solution 2:

500 mL of water

60 g of salt

a)

Not enough information to tell

b)

Solution 1

c)

Solution 2

d)

They are equally diluted

5.

Calculate the mass percent of solution, if there is 100 g of sugar and 400 g of water

a)

30 %

b)

25 %

c)

20 %

d)

15 %

6.

How many liters would you need to make a 1 M solution if you have 6 mol of Sodium Hydroxide?

a)

2 lt

b)

3 lt

c)

4 lt

d)

6 lt

7.
What is the molarity of 4 g of NaCl (MM=58.45) in 3,800 mL of solution?
a)
0.018 M
b)
0.0011 M
c)
1.052 M
d)
0.062 M
8.
How many grams of solute are dissolved in 125.0 mL of 5.00 M NaCl (MM = 58.45)?
a)
0.625 g NaCl
b)
625 g NaCl
c)
36.5 g NaCl
d)
0.04 mol NaCl
9.

Molality (m) = moles of solute / _________________________.

a)

per kilogram of solvent

b)

kiloliter of solvent

c)

kilometer of solvent

d)

ounces of solvent

10.

What is the molality of a solution made by dissolving 2 moles of NaOH in 400 grams of water?

a)

5 mol/kg. solvent

b)

4 mol/kg solvent

c)

3 mol/kg. solvent

d)

2.5 moles /kg solvent

11.
Total number of mol fraction for all component in the solution is equal to
a)
1.0
b)
0.95
c)
0.50
d)
2.0
12.

Calculate mol fraction of H2O in 1.33 molal NaOH solution.

(Hint: Molality is no of moles of solute in 1000g of solvent)

a)

0.56

b)

0.76

c)

0.98

d)

0.84

13.
Calculate mol fraction of H2O in 1.33 molal NaOH solution.
a)
0.56
b)
0.76
c)
0.98
d)
0.84
14.

Calculate the mole fraction of benzene (C6H6) in a solution of 46.8 g benzene and 36.8 g of toluene (C6H5CH3).

[Mol wt of benzene : 78, mol wt of toluene: 92]

a)

0.4

b)

0.6

c)

0.7

d)

0.5

15.

Units of molality is:

a)

moles per litre

b)

moles per kg

c)

no units

d)

mol L-1