wayground logo

Free Printable Worksheets

NEW

Font size

S
M
L
XL
Worksheets

Chemistry- Mole Concept

Total questions: 12

Worksheet time: 27mins

Name
Class
Date
1.
How many molecules of sugar (C6H12O6) are in a mole?
a)
24 molecules
b)
180 molecules
c)
180 g
d)
6.02 x 1023 molecules
2.

How many grams are in 1.2 x 1024 molecules of CO? (molar mass of CO = 28 g/mol)

a)

28.2 g

b)

55.8 g

c)

6.02 g

d)

1.2 g

3.

How many atoms of carbon are in 6.00 g of carbon?

a)

1.20x1024 atoms C

b)

6.02x1023 atoms C

c)

3.01x1023 atoms C

d)

1.50x1023 atoms C

4.

How many moles are in 3.01 x 1022 atoms of magnesium?

a)

0.05 moles

b)

1.81 x 1046 moles

c)

5.00 x 1021 moles

d)

5 moles

5.
What is the definition for Avogadro's number?
a)
number of grams per one mole of a substance
b)
whole number ratio that is a multiple of a chemical formula
c)
simplest, whole number ratio of a chemical formula
d)
6.02 x 10^23 particles per one mole of a substance
6.

What is the molarity of 4 g of NaCl (Mr NaCl=58.45 g mol-1) in 3800 mL of solution?

a)

0.018 M

b)

0.0011 M

c)

1.052 M

d)

0.062 M

7.
What is the molarity of a solution made by diluting 26.5 mL of 6.00M HNO3 to a volume of 250 mL?
a)
15.9 M
b)
0.636 M
c)
0.642 M
d)
1.59 M
8.

Number of atoms in 52 g of He are:

a)

2.865 X 1023

b)

7.83 X 1024

c)

6.023 X 1023

d)

5000

9.

How many moles of methane are required to produce 22g of CO2(g) after combustion ?

a)

2 Moles

b)

1 Moles

c)

0.5 Moles

d)

0.05 Moles

10.

The amount of KClO3 needed to supply sufficient oxygen for burning 112 L of CO gas at N.T.P is___________.

a)

9.859 g

b)

6.023 g

c)

308.25 g

d)

204.16 g

11.

Calculate the total number of electrons present in 3.2 g of CH4.

a)

12.044×102312.044\times10^{23}

b)

6.022×10246.022\times10^{24}

c)

3.011×10243.011\times10^{24}

d)

24.088×102424.088\times10^{24}

12.

The atomic masses of two elements (P and Q) are 20 and 40 respectively. x g of P contains y atoms, how many atoms are present in 2x g of Q?

a)

4y

b)

2y

c)

y

d)

None of the above