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11×3+12×4+13×5+⋅⋅⋅+122×24+123×25=?\frac{1}{1\times3}+\frac{1}{2\times4}+\frac{1}{3\times5}+\cdot\cdot\cdot+\frac{1}{22\times24}+\frac{1}{23\times25}=?1×31+2×41+3×51+⋅⋅⋅+22×241+23×251=?
851600\frac{851}{600}600851
449600\frac{449}{600}600449
222
8511200\frac{851}{1200}1200851
3x+1=a(x-b)의 해가 무수히 많을 때, ab의 값을 구하시오.
3
1
-3
-1
(a)
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8 questions
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