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WorksheetsFinal Exam Reviewer
Total questions: 47
Worksheet time: 4hrs 52mins
When a function gets closer and closer to 7 as the variable gets closer to 4 the limit of the function?
equals 4
equals 7
does not exist
cannot be determined
Evaluate x→−4lim x2−164x+16 using table of values
∞
−∞
0.5
-0.5
Evaluate x→2+lim g(x) given the graph .
2
-1
0
1
Evaluate x→−1+lim f(x) given the graph.
∞
- ∞
-2
-1
Given , f(x) = x2−1 if x > 2, and x − 4 if x ≤ 2 , x→2−limf(x) Given the piecewise function, evaluate the given limit.
3
2
-2
-3
Given the piecewise function f(x)= x2−1 , if x > 3 , x − 4 , if x ≥3 evalaute f(3)
-1
8
0
DNE
Evaluate x→3lim(x2+7x−5)
25
19
14
-25
Evaluate x→1limx+38x+1
29
29
49
23
Evaluate x→−3lim x2+4x+3x2+x−6
210
25
2−5
2−3
Evaluate x→1lim x+3−2x−1
indeterminate
undefined
4
-4
Evaluate x→−∞lim 4y2−5y+25y3−2y2+y − 7
−∞
∞
45
0
Evaluate x→9lim 3−x9−x
indeterminate
6
12
9
Evaluate x→2lim x−2x2−5x+6
5
undefined
-1
indeterminate
Evaluate x→2lim x4−16x3−8
12
undefined
indeterminate
1
If f(x)=x−4x2−16 , why does f(4) does not exist?
4 is not the domain of the function
its indeterminate in form
the vertical asymptote is x = 4
the function is undefined
x→∞lim (41)x
−∞
∞
1
0
Evaluate x→0lim xsin 2x using table of values
0.959
0.998
1.999
1
Evaluate x→∞lim e3x−5
0
3x-5
∞
e3x−5
Evaluate x→ 3lim [log23 x2−17x+6]
(a)
Evaluate x→2πlim tan2x
(a)
Evaluate x→0lim sin πxsin 21x
(a)
Evaluate x→0lim xsin 43x
(a)
Evaluate x→0lim sin 7xsin 5x
(a)
Evaluate x→0lim 7x1−cos 9x
(a)
Evaluate x→−∞lim ex+e2xe4x+2 . Show your solution
∞
−∞
0
1
The function f(x)=x2−9x−3 is continuous at _____
5
3
-3
Find the derivative of f(x)= 4x3−8x2+4x using differentiation rule.
f′(x)=12x2−16x+4
f′(x)=4x2−8x
f(x)=12x2−16x+4
f(x)=12x2−16x
What is the equation of the tangent line to the curve y=x2−2x−3 at (-1,0). Express in general form
(a)
What is the slope of the tangent line to the graph of the function f(x)=2x3−3x2 at a given point
f′(x)=6x2
f′(x) = 2x2−3x
f′(x)=6x2−6
f′(x) = 6x2−6x
What is the slope of the tangent curve y=3x2+6x+2 at (-2,1)?
(a)
Identify the type of discontinuity f(x) = x2+4x+5x2+7x+10
removable ata x = 5, infinite at x = -1
infinite at x = -1
removable at x = -5 , infinite at x = 1
infinite at x = 2
Identify the type of discontinuity f(x)=x−4x2−1
infinite at x = 4
removable at x = 4
the function is continuous
jump at x = 4
Name the discontinuity at x = 2 given the graph
infinite
jump
removable
continuous at x = 2
What will make the function f(x)= x2−43x2+8 continuous?
2
3
-2
-3
If a function f has a domain (−∞,∞) , then it is ____
increasing
continuous
extraneous
undefined
Assume f(x) is continuous over the interval [-2,3] . The function f has at least how many zeros?
1
2
3
4
Consider the function f(x)=x−31−5 ,Can you conclude that there must be a zero between f(2) and f(3.1)?
Yes, because f(2) is negative and f(3.1) is positive.
No, because f(2) is negative and f(3.1) is also negative.
Yes, because f(2) is positive and f(3.1) is negative.
No, because there is a discontinuity at x = 3.
Which of the intervals is NOT continuous of the function f(x)=x−4x2+x−20
((0,∞))
[0,∞]
(0,2)
(1,2)
Which of the following is false to determine that there is a solution to the given function f(x)=x3−x−1 between x = 1 and x = 2
There is more than one solution on the interval [1,2].
The function is continuous because it is a polynomial function
It is defined on the closed interval [1,2]
If f(x)=0, then -1< 0 < 5
Which of the following is false to prove that the function f(x)= x4 +x3 −3x2 +2x −4 has a zero on the closed interval [-2,2]?
if f(x)= 0 , then -12 < 0 < 12
f(-2)=12, f(12)=12
The function has a zero on [-2,2]
The function has more than one zero on the closed interval
Find the third derivative of the function f(x)= x5 −x4+2x3−3x2+5x+9
f′′′ = 20x3−12x2+12x−6
f′′′=60x2−24x+12
f′′′ = 5x4−4x3+6x2−6x+5
f′′′=120x − 24
Find the first derivative of y=x31+2x
y′=x3−3+2x
y′=x2−3+2
y′ = x43+2x
y′=x4−3+2
Find the first derivative of f(x)=41x5−31x3+2
f′(x)=4x45−x2
f′(x)=45x4−x2
f′(x)=45x4−3x2
f′(x)=45x4−x
Find the derivative of y = (x3+2x)(2x−1) .
dxdy=2x3+4x − 2
dxdy=8x3−3x2+8x−2
dxdy=8x3+3x2+8x +2
dxdy=8x3−3x2+8x
Find dxdy given y=x3−1x2+1
dxdy=(x3−1)2x(x3+3x+2)
dxdy=(x3−1)22x4−2x−3x4−3x2
A particle moves in one direction along a line so that after t seconds its distance is given by s(t)=6t4−6t2 meters from the origin. Find the instantaneous velocity at t = 3 seconds
486 m/s
390 m/s
648 m/s
612 m/s
Which of the following solution is FALSE for the derivative of y with respect to x for y=x2−2x .
