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Grade 6 EOG Review

Total questions: 14

Worksheet time: 28mins

Name
Class
Date
1.

Which would you solve first in this expression?  (52−10)÷5×23\left(5^2-10\right)\div5\times2^3  

a)

 232^3  

b)

 525^2  

c)

 5×25\times2  

d)

 10÷510\div5  

2.

 (52−10)÷5×23\left(5^2-10\right)\div5\times2^3  

In this expression, what is the value of the last term?

a)

10

b)

25

c)

6

d)

8

3.


 (52−10)÷5×23\left(5^2-10\right)\div5\times2^3  
Solve inside the parenthesis.

a)

0

b)

15

c)

25

d)

35

4.

 (52−10)÷5×23\left(5^2-10\right)\div5\times2^3  
Solve.

a)

24

b)

18

c)

1/2

d)

0

5.

HOW WOULD YOU SOLVE THIS PROBLEM?

Ja'Maya had a job during summer vacation. She earned $8.50 an hour. She worked 5 hours a week for 8 weeks. How much money did she earn?

a)

Add all the numbers together.

b)

Multiply 5 and 8, then add $8.50.

c)

Multiply the product of 5 and 8 by $8.50.

d)

Multiply $8.50 by 5 hours, then divide by 8.

6.

SOLVE.

Ja'Maya had a job during summer vacation. She earned $8.50 an hour. She worked 5 hours a week for 8 weeks. How much money did she earn?

a)

$48.50

b)

$110.50

c)

$340

d)

$3,000

7.

 25x+10y25x+10y  

What is the GCF of the two coefficients in the expression?

a)

2

b)

5

c)

10

d)

25

8.

 25x+10y25x+10y  
Which expression is equivalent?

a)

 5(5x+2y)5\left(5x+2y\right)  

b)

 5(5x+10y)5\left(5x+10y\right)  

c)

 5(20x+5y)5\left(20x+5y\right)  

d)

 5(20x+10y)5\left(20x+10y\right)  

9.

 45+5x−x+3445+5x-x+\frac{3}{4}  
How many terms are in the expression?

a)

two

b)

three

c)

four

d)

five

10.

 45+5x−x+3445+5x-x+\frac{3}{4}  
Simplify this expression.

a)

 45+4x+3445+4x+\frac{3}{4}  

b)

 50 34x50\ \frac{3}{4}x  

c)

 50x−34x50x-\frac{3}{4}x  

d)

 45 34+4x45\ \frac{3}{4}+4x  

11.

How would you find the volume of this solid figure?

a)

2 12+2 12+3 142\ \frac{1}{2}+2\ \frac{1}{2}+3\ \frac{1}{4}

b)

2 12×2 12×3 142\ \frac{1}{2}\times2\ \frac{1}{2}\times3\ \frac{1}{4}

c)

(2 12×2 12)+3 14\left(2\ \frac{1}{2}\times2\ \frac{1}{2}\right)+3\ \frac{1}{4}

d)

3 14(2 12+2 12)3\ \frac{1}{4}\left(2\ \frac{1}{2}+2\ \frac{1}{2}\right)

12.

What is the first step?

a)

Add 5r and 1/5

b)

Multiply 5 and 0

c)

Multiply 1/5 by 1/5

d)

This problem cannot be solved.

13.

Solve.

a)

1/10

b)

1/25

c)

2/10

d)

50+2/10

14.

If one negative and one positive create a zero pair, what is the sum?

a)
b)
c)
d)