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QUIZIZZ 4.1: HINGE THEOREM

Total questions: 10

Worksheet time: 8mins

Name
Class
Date
1.

What theorem states that "If two sides of a Δ\Delta are  \cong to two sides of another  Δ\Delta  , and the included  \angle s are not  \cong , then the longer third side is opposite the larger included angle." ? 

a)

Vertical Angle Theorem

b)

SAA Theorem

c)

PAIC Theorem 

d)

Hinge Theorem

2.

The Hinge Theorem is also called _______________________.

a)

SSS Inequality Theorem

b)

SAS Inequality Theorem

c)

ASA Inequality Theorem

d)

SAA Inequality Theorem

3.

The Converse of the Hinge Theorem is also called _______________________.

a)

SSS Inequality Theorem

b)

SAS Inequality Theorem

c)

ASA Inequality Theorem

d)

SAA Inequality Theorem

4.

What conclusion can be drawn in the illustration if  SR>MJ\overline{SR}>\overline{MJ} ?

a)

 x>y\angle x>\angle y  

b)

 x>z\angle x>\angle z  

c)

 z>x\angle z>\angle x  

d)

 z<x\angle z<\angle x  

5.

It is called the HINGE theorem, because...

a)

the vertex of the angle acts like a hinge to open the triangle.

b)

it's named after Joseph Hinge, the man who discovered it.

c)

"hinge" is the Spanish word for angle.

d)

the triangle makes a hinge shape, like a tent.

6.

Which inequality relates GBC and FBA\angle GBC\ and\ \angle FBA ?

a)

mGBC <mFBAm\angle GBC\ <m\angle FBA

b)

mGBC > mFBAm\angle GBC\ >\ m\angle FBA

c)

mGBC mFBAm\angle GBC\ \le\ m\angle FBA

d)

mGBC mFBAm\angle GBC\ \ge\ m\angle FBA

7.

Four students are doing a scavenger hunt starting at the water fountain. They disagree one the directions and split up. Their paths are shown in the diagram. Which pair is closest to the fountain when they stop?

a)

Luther and Stephanie

b)

Mario and Lee

8.
Which of the following is a possible  length for segment AC
a)
10
b)
15
c)
17
d)
9
9.
Using the hinge theorem, we can say that Angle 1 _____ Angle 2.
a)
Less than
b)
Greater than
c)
Equal to 
d)
Half of
10.

Compare QT and ST

a)

QT < STQT\ <\ ST

b)

QT > STQT\ >\ ST

c)

QT = STQT\ =\ ST

d)

QT ST\overline{QT}\ \cong\ \overline{ST}