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Calcular ‘‘x’’, si: sen(x+10°) = cos(x+20°)
20°
30°
25°
40°
Calcula el valor de "x" si: cos(3x + 10°) sec(x + 18°) = 1
8°
4°
10°
28°
Hallar "x":
Sen(2x+10) . Csc ( 5x-20) = 1
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tg(3x+ 5) = Ctg (40)
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Hallar "x": Csc (3x +16) = Sec (2x +24)
Sabiendo que: Sen(2x+15°).Csc65°=1Sen\left(2x+15°\right).Csc65°=1Sen(2x+15°).Csc65°=1 Calcula el valor de "x"
15°
35°
Siendo: Tg(α+20°)=Ctg(α−10°)Tg\left(\alpha+20°\right)=Ctg\left(\alpha-10°\right)Tg(α+20°)=Ctg(α−10°) Halla el valor de α\alphaα
50°
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10 questions
แบบทดสอบ บทที่ 1 อสมการเชิงเส้นตัวแปรเดียว
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