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Elastic constants and principal planes

Total questions: 19

Worksheet time: 20mins

Name
Class
Date
1.

The length of material which undergoes a change in temperature also changes and if the material is free

a)

No stress is induced

b)

compressive stress is induced

c)

Tensile stress is induced

d)

None of these

2.

If the bar is constrained and is prevented from expansion, the temperature stress induced in the material is


a)

No Stress

b)


 αtE\alpha tE  

c)

 αE\alpha E  

d)

 αt\alpha t  

3.

A metal bar of length 100 mm is inserted between two rigid supports and its temperature is increased by 10º C. If the coefficient of thermal expansion is 12 x 10-6 per ºC and the Young’s modulus is 2 x105MPa, the stress in the bar is

a)

Zero

b)

12 MPa

c)

24 MPa

d)

2400 MPa

4.

Principal Planes are the planes on which

a)

Shear Stress is maximum

b)

Shear stress is zero

c)

Normal stress does not exist

d)

None of these

5.

Principal stresses are normal stresses that acts on Principal Plane

a)

True

b)

False

6.

Principal Planes are

a)

Perpendicular to each other

b)

Parallel to each other

7.

Ratio of lateral strain to longitudinal strain is called

a)

Bulk Modulus

b)

Youngs Modulus

c)

Poision Ratio

8.

Ratio of hydro static pressure to volumetric strain is called

a)

Bulk Modulus

b)

Shear Modulus

c)

Modulus of Rigidity

9.

The relationship between Young’s modulus can be expressed in terms of bulk modulus (K) and rigidity modulus (G) as 

a)

 E=3K(1−2v)E=3K\left(1-2v\right)  

b)

 E=2G(1+v)E=2G\left(1+v\right)  

c)

 E=9KG3K+GE=\frac{9KG}{3K+G}  

d)

None of these

10.

In the case of an engineering material under unidirectional stress in the x- direction,the Poisson's ratio is equal to (symbols have the usual meanings)

a)

eyex\frac{e_y}{e_x}

b)

σxey\frac{σ_x}{e_y}

c)

σxσy\frac{σ_x}{σ_y}

d)

None of this

11.

A rod of length L and diameter D is subjected to a tensile load P. Which of the following is sufficient to calculate the resulting change in diameter?

a)

Young Modulus

b)

Shear Modulus

c)

Poisson Ratio

d)

Both shear Modulus and Young Modulus

12.

Compressibility is the inverse of bulk modulus.

a)

True

b)

False

13.

For the same amount of force applied, what is the stress on a given object if the surface area is halved?

a)

half the original

b)

remain unchanged

c)

twice the original

14.

Choose the right formula for the figure shown.

a)

eV=(σx+σy+σz)E(1−2μ)e_V=\frac{\left(\sigma_x+\sigma_y+\sigma_z\right)}{E}\left(1-2\mu\right)

b)

eV=(σx−σy−σz)E(1−2μ)e_V=\frac{\left(\sigma_x-\sigma_y-\sigma_z\right)}{E}\left(1-2\mu\right)

c)

eV=(−σy−σz)E(1−2μ)e_V=\frac{\left(-\sigma_y-\sigma_z\right)}{E}\left(1-2\mu\right)

d)

None of the choices

15.

Choose the right formula for the figure shown.

a)

eV=(σx+σy+σz)E(1−2μ)e_V=\frac{\left(\sigma_x+\sigma_y+\sigma_z\right)}{E}\left(1-2\mu\right)

b)

eV=(σx−σy−σz)E(1−2μ)e_V=\frac{\left(\sigma_x-\sigma_y-\sigma_z\right)}{E}\left(1-2\mu\right)

c)

eV=(−σy−σz)E(1−2μ)e_V=\frac{\left(-\sigma_y-\sigma_z\right)}{E}\left(1-2\mu\right)

d)

None of the choices

16.

The formula for Bulk Modulus is

a)

σeV\frac{\sigma}{e_V}

b)

τeV\frac{\tau}{e_V}

c)

τϕ\frac{\tau}{\phi}

d)

Volumetric StressVolumetric strain\frac{Volumetric\ Stress}{Volumetric\ strain}

17.

The formula for Shear Modulus is

a)

σeV\frac{\sigma}{e_V}

b)

τeV\frac{\tau}{e_V}

c)

τϕ\frac{\tau}{\phi}

d)

Volumetric StressVolumetric strain\frac{Volumetric\ Stress}{Volumetric\ strain}

18.

The relationship between Young’s modulus (E), bulk modulus (K) and Poisson’s ratio (µ) is expressed as 

a)

 E=3K(1−2v)E=3K\left(1-2v\right)  

b)

 E=2G(1+v)E=2G\left(1+v\right)  

c)

 E=9KG3K+GE=\frac{9KG}{3K+G}  

d)

None of these

19.

The relationship between Young’s modulus (E), rigidity modulus (G) and Poisson’s ratio (µ) is expressed as 

a)

 E=3K(1−2v)E=3K\left(1-2v\right)  

b)

 E=2G(1+v)E=2G\left(1+v\right)  

c)

 E=9KG3K+GE=\frac{9KG}{3K+G}  

d)

None of these