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次の2次関数のグラフの頂点を求めよ。
(0,0)\left(0,0\right)(0,0)
(1,0)\left(1,0\right)(1,0)
(0,2)\left(0,2\right)(0,2)
(1,1)\left(1,1\right)(1,1)
次の2次関数のグラフの頂点を求めよ。 y=-x^2y=−x2
(−1,0)\left(-1,0\right)(−1,0)
(−1,1)\left(-1,1\right)(−1,1)
(0,−1)\left(0,-1\right)(0,−1)
(2,−1)\left(2,-1\right)(2,−1)
(2,2)\left(2,2\right)(2,2)
(0,1)\left(0,1\right)(0,1)
(2,1)\left(2,1\right)(2,1)
y=(x+2)2−5y=\left(x+2\right)^2-5y=(x+2)2−5
(−2,−5)\left(-2,-5\right)(−2,−5)
(2,−5)\left(2,-5\right)(2,−5)
(−2,5)\left(-2,5\right)(−2,5)
(2,5)\left(2,5\right)(2,5)
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10 questions
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