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WorksheetsModern Physics-03 Matter Waves
Total questions: 16
Worksheet time: 18mins
Electron has energy of 100 eV what will be its
wavelength
1.2 A
10 A
100 A
1 A
The ratio of wavelength of deutron and proton
accelerated through the same potential difference
will be
21
2
21
2
An electron is accelerated from rest, between two
points A and B at which the potentials are 20V and
40 V respectively. The De Broglie wavelength
associated with the electron at B will be -
0.75 A
7.5 A
2.75 A
2.75 m
The magnitude of De broglie wavelength λ of
electron (e), proton (p), neutron (n) and α - particle
all having the same kinetic energy of 1MeV, then which one is correct :
λe>λp>λn>λα
λe>λn>λp>λα
λα>λp>λn>λe
λα>λn>λp>λe
The wavelength of very fast moving electron
(v≈c) is :
λ=m0vh
λ=2mEh
λ2=2mEh2
λ=m0vh1−c2v2
In davisson-Germer experiment, the filament
emits :-
Photons
Protons
X - rays
Electrons
If given particles are moving with same velocity,
then maximum de-Broglie wavelength for :
Proton
Neutron
Alpha Particle
Beta Particle
If λp and λα be the wavelengths of protons and
α -particles of equal kinetic energies, then
λp=4λα
λp=2λα
λp=λα
λp=2λα
Electrons used in an electron microscope are
accelerated by a voltage of 25 kV. If the voltage
is increased to 100 kV then the de-Broglie
wavelength associated with the electrons would :
increase by 2 times
decrease by 2 times
decrease by 4 times
increase by 4 times
If velocity of a particle is 3 times of that of electron
and ratio of de brogile wavelength of particle to that
of electron is 1.814×10−4 . The particle will be :-
Neutron
Deutron
Alpha
Tritium
Light of wavelength 500 nm is incident on a metal
with work function 2.28 eV. The de Broglie
wavelength of the emitted electron is :-
≤2.8×10−12m
<2.8×10−12m
<2.8×10−9m
≥2.8×10−9m
An electron with with rest mass m0 moves with a speed
of 0.8C. Its mass when it moves with this speed is :
m0
6m0
35m0
53m0
The de Broglie wavelength of an electron moving
with a velocity 1.5×108 sesm is equal to that of
a photon. The ratio of the kinetic energy of the
electron to the energy of the photon is
41
21
2
4
The de Broglie wavelength of a particle is the same as the wavelength of photon. Then, the photon’s energy is:
equal to the kinetic energy of the particle.
less than kinetic energy of the particle.
greater than kinetic energy of the particle.
nothing can be specified.
A photoelectric material having work function ϕ0 is illuminated with light of wavelength λ(λ<ϕ0hc) . The fastest photoelectron has a de Broglie wavelength λd . A change in the wavelength of the incident light by Δλ results in change Δλd in λd . Then the relation ΔλΔλd is proportional to
λ2λd2
λλd
λλd3
λ2λd3
If E and P are the energy and the momentum of
a photon respectively then on reducing the
wavelength of photon -
P and E both will decrease
P and E both will increase
P will increase and E will decrease
P will decrease and E will increase
