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Equilibrium of Force

Total questions: 15

Worksheet time: 29mins

Name
Class
Date
1.
Static Equilibrium means ____
a)
Objects at rest
b)
moving objects
c)
that which is in outer space
d)
electrical balance
2.
Dynamic Equilibrium means ___________
a)
Objects at rest
b)
objects moving at constant speed in a straight-line path 
c)
force of friction
d)
flying in outer space
3.

The moment of a force causes an object to

a)

move forward

b)

move backward

c)

stop moving

d)

turn about a fixed point

4.

The turning effect of a force on a door is greater when it is applied at

a)

A point near the hinges and perpendicular to the door

b)

A point near the hinges and parallel to the door

c)

A point far away from the hinges and perpendicular to the door

d)

A point far away from the hinges and parallel to the door

5.

Jack has a weight of 300 N and sits 2.0 m from the pivot of see-saw. Jill has a weight of 450 N and sits 1.5 m from pivot. Who will move down?

a)

Jack

b)

Jill

c)

Both of them

d)

None of them

6.

What is the force F needed to balance the bar shown?

a)

3

b)

4

c)

6

d)

8

7.

A light metre rule is allowed to pivot freely at the zero end. The other end is supported by a spring balance. A weight of 200N is then hung at the 40cm mark. The metre rule stays horizontal. What is the reading on the spring balance?

a)

80

b)

40

c)

8

d)

4

8.

Which one of the following activities does not apply the turning effect of a force?

a)

swinging on a swing

b)

sliding down a slide

c)

moving up and down on the see-saw

d)

rowing a boat

9.

A nut has been tightened by a force of 180 N using 8 cm long spanner. What length of a spanner is required to loosen the same nut with 150 N force

a)

11 cm

b)

8.5 cm

c)

9.6 cm

d)

10.9 cm

10.

A force of 120 N is applied perpendicularly on a spanner at a distance of 9 cm from a nut. The torque produced by the force will be

a)

12 Nm

b)

10.8 Nm

c)

15 Nm

d)

12.59 Nm

11.

A boy of weight 600N sits on the see-saw as shown at a distance of 1.5m from the pivot. What is the force F required at the other end to balance the see-saw?

a)

450 N

b)

350 N

c)

4.5 N

d)

200 N

12.

The figure shows a uniform metre rule pivoted at the 50cm mark. 125g and 200g weights hang from the rule as shown. Calculate where you would hang a 25g mass in order to balance the rule horizontally

a)

20 cm from pivot on the side of 125 g mass

b)

10 cm from pivot on the side of 125 g mass

c)

40 cm from pivot on the side of 200 g mass

d)

10 cm from pivot on the side of 200 g mass

13.

When an object is in equilibrium, which equation is true?

a)

Clockwise moment = anticlockwise moment

b)

Clockwise moment + anticlockwise moment = 0

c)

Clockwise moment / anticlockwise moment = 0

d)

Clockwise moment + anticlockwise moment = resultant force

14.

Calculate the tension force 1 (T1).

(a)  

15.

Look at the figure.

System is in static equilibrium. The tension of string is 80 N.

Determine the value of d.

(a)