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WorksheetsQUARTER 2 Benchmark Review Algebra II
Total questions: 28
Worksheet time: 52mins
f(x)=7x2−36x+57x−1
Find the horizontal asymptote, the vertical asymptote, and the hole, if they exixt.
HA: y = 0, VA: x = 5, hole: x = 1/7
HA: NONE , VA: x = 5, hole: x = -1/7
HA: y = 0, VA: x = - 5, hole: x = -1/7
HA: y = 7, VA: x = 5, hole: NONE
y=x−92
Name the domain.
(- ∞, 2) U (2, ∞ )
( - ∞ , - 2 ] U [ - 2 , ∞ )
( - ∞ , 9 ) U ( 9 , ∞ )
( - ∞ , 9 ] U [ 9 , ∞ )
x2+2x−153x2+15x
Simplify.
x−13
x−33x
x−31
x+53x
−x22+71=7x5 Solve.
( 2 , 7 }
{ - 7 }
{ - 7 , 2 }
{ - 2 , 7 }
Which of the following is the graph of
f(x)=x−4x
107x+2−3x+6=
1311x−76
3031x+54
3011x+66
3011x−54
Simplify.
x−8x2−4x+4⋅x2−11x+18x2−81
x−9(x−2)(x+8)
x−8(x−2)(x+9)
x−2
x+8
x−5x−3+x−84=x2−13x+402x−10
x = 5, x = 8
x = 2, x = 7
x = 5, x = 7
x = - 2, x = 9
Factor x3 +7x2 + 2x - 40 completely, if one of the factors is (x - 2 ).
(x - 2 )(x + 2)(x + 10)
(x - 2 )(x - 2)(x - 10)
(x - 2 )(x + 1 )( x + 20 )
( x - 2 )( x + 5 )( x + 4 )
Simplify. ( 9 + 7i ) ( 4 - 5i )
71 - 17i
1 + 17i
1 - 73i
71 + 73i
Find the EXTRANEOUS solution to
x+16=x − 4
x = - 9
x = 9
x = 0 and x = 9
x = 0
Factor: x2 + 11xy - 12y2
( x + 3y )( x - 4y )
( x + y )( x - 12y )
( x - y )( x + 12y )
( x + 2y )( x - 6y)
Name the domain and the range.
Domain: All real numbers
Range: y > 5
Domain: All real numbers
Range: y > - 5
Domain: All real numbers
Range: y < - 5
Domain: All real numbers
Range: y < 5
Simplify.
Find the perimeter.
35−2+57=
15−25+25
15−25+535
5−2+535
45−25+57
64m9n6=
8m92n3
32m29n3
8m29n3
32m92n21
(3−47)
One side of a square is shown above. Find the area of the square.
115
115−421
−109−421
115−821
5x+17=7x−9
Find the solution.
x = 13
x = - 13
x = 4
x = 6
Solve.
x = 2319
x = 79
x = 19
x = 49
18(2+6)+53
Simplify the expression.
6+227+53
6−116
18+303
6+113
−148
Simplify.
4i37
2i37
−237
−437
Which equation is graphed here?
Name the domain.
{ x | x < 1 }
{ x | x > 1 }
{ x | x < - 1 }
{ x | x > 2 }
Write with a rational exponent.
m211
m611
m21
m3
x2−51=6
{1031}
{−107}
{3110}
{0}
v=m2K
The formula to find the velocity of an object is shown above. "v" is measured in m/sec, K, kinetic energy, is measured in Joules. "m" is the mass of the object measured in kg. Solve the equation for m.
m=2K2
m=K2v2
m=2Kv2
m=v22K
m=v22K
The formula to find the mass of an object is shown above. "v" is measured in m/sec, K, kinetic energy, is measured in Joules. "m" is the mass of the object measured in kg. Find the mass if the object has a kinetic energy of 2900 Joules and is traveling at a velocity of 15 meters per second.
~ 12.89 kg
~ 25.78 kg
~ 193.33 kg
~ 386.67 kg
