WorksheetsQuadratics Review - Graphing & Solving
Total questions: 31
Worksheet time: 3hrs 41mins
y = 3(x + 5)2 - 4,
what is the vertex of the parabola?
y=-(x-4)2-3,
does this parabola have a maximum or minimum value?
y=x2+6x+4 What are the coordinates of the vertex?
(a)
What are the coordinates of the vertex? Is it a maximum or a minimum?
(2, 3); minimum
(2, 5); maximum
(2, 3); maximum
(2, -3); minimum
(2, -3); maximum
What are the coordinates of the y - intercept?
(a)
The parabola y = x2 - 2x + 4 will
open up
open down
The parabola y = - 2x2 - 4x + 1 will have an axis of symmetry of
x = - 1
x = 1
x = 4
x = - 4
The vertex of parabola y = - 2x2 - 4x + 1 is
(1, 3)
(- 1, 3)
(- 1, -5)
(- 1, 5)
Solve for x
x2 = 64
x = 8, -8
x = 32, -32
x = 4, -4
No real solution
k2 - 6 = 43
Solve for x
3x2 - 27 = 0
x = 4.9, -4.9
x = 9, -9
x = 3, -3
No solution
Solve: x2+8=28
No solution
x=±45
x=±6
x=±25
Select the solution(s) for the quadratic: x2−11x+19=−5
3
8
-9
-3
x2 = 9 - 4x
a2 + 10a + 21 = 0
x2 - 4x + 4 = 20,
what goes in the blank?
(x - __ )2 = 20
x2 + 6x = 5
Complete the square for 2x2 - 12x + ____
2x2 - 12x + 144
2x2 - 12x + 36
2x2 - 12x - 36
2x2 - 12x + 18
x2 + 12x + ____
Complete the square for 3x2 + 24x + ____
3x2 + 24x + 144
3x2 + 24x + 36
3x2 + 24x + 16
3x2 + 24x + 48
Solve by completing the square:
v2 + 6v − 59 = 0
{-5 + √50, -5 - √50}
{5 + √50, 5 - √50}
{-3 + √68, -3 - √68}
{3 + √68, 3 - √68}
a, b, and c for
the quadratic equation:
4x2 – 8x = 3
The discriminant is
ax2 + bx + c
b - 4ac
b2 - 4ac
b2 + 4ac
