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(x−4)3−5=0\ \ \ \frac{\left(x-4\right)}{3}-5=0 3(x−4)−5=0 Resolver:
191919
151515
333
101010
x2+2−x12=x6−54\frac{x}{2}+2-\frac{x}{12}=\frac{x}{6}-\frac{5}{4}2x+2−12x=6x−45 Encuentra el valor de "x" en la ecuación:
−13-13−13
131313
−113-\frac{1}{13}−131
113\frac{1}{13}131
2x−13−x+1324=3x+5(x+1)8\frac{2x-1}{3}-\frac{x+13}{24}=3x+\frac{5\left(x+1\right)}{8}32x−1−24x+13=3x+85(x+1) Resuelve:
−12-\frac{1}{2}−21
12\frac{1}{2}21
222
−2-2−2
10x−8x−34=2(x−3)10x-\frac{8x-3}{4}=2\left(x-3\right)10x−48x−3=2(x−3) Encuentra la raíz de la siguiente ecuación:
−98-\frac{9}{8}−89
98\frac{9}{8}89
999
−8-8−8
12(x−1)−(x−3)=13(x+3)+16\frac{1}{2}\left(x-1\right)-\left(x-3\right)=\frac{1}{3}\left(x+3\right)+\frac{1}{6}21(x−1)−(x−3)=31(x+3)+61 Resuelve:
85\frac{8}{5}58
1 151\ \frac{1}{5}1 51
−34-\frac{3}{4}−43
−92-\frac{9}{2}−29
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10 questions
N2-T27-Circunferencia - partes
Worksheet
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Professional Development
N1-T9-Ecuaciones ax + b = c, x/a + b = c o con -
Theodore8910
KG - Professional Dev...
GCE BERBAGI SERI 7
BÀI 106 NHÂN SỐ CÓ BỐN CHỮ SỐ
EXAMEN NUMEROS COMPLEJOS
Test tuần 06-10.12.2021
Lit man