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Exam 3 Review

Total questions: 14

Worksheet time: 14mins

Name
Class
Date
1.

Which proton would be abstracted (C2 or C6), and why?

a)

Either proton would be abstracted equally.

b)

Can't determine - It depends on in the nucleophile is bulky or narrow

c)

C2, because the proton must be anti peri planer

d)

C6 because the proton must be anti peri planar

2.

Which step is involved in a halohydrin formation?

a)

Initial attack by bromine

b)

Formation of a carbocation

c)

Attack by water on brominium ion

d)

Attack by bromine on brominium ion

3.

What would be the product of this two-step reaction?

a)
b)
c)
d)

None of these choices

4.

What type of reaction is this?

a)

Hydroboration-Oxir

b)

Oxymercuration-Demercuration

c)

Acid-catalyzed hydration

d)

Halohydration

5.
a)
b)
c)
d)
6.

What is the major product?

a)
b)
c)
7.

What is the rate determining step in an SN1 reaction?

a)

LG leaves, making a carbocation

b)

Nucleophile attacks, making protonated product

c)

Deprotonation to make final product

8.
a)
b)
c)
d)
9.

What is the product of the two step reaction sequence?

a)
b)
c)
d)

More than one of these choices

10.

How many peaks (unique signals) would you epect to find in the proton NMR spectrum of CH3CH2OCH2OCH2CH3

a)

3

b)

4

c)

5

d)

6

11.
a)

I

b)

II

c)

III

d)

IV

12.

Treating 1-methylcyclohexene with HCl would yield primarily which of these?

a)
b)
c)
13.
a)

I & II

b)

III & IV

c)

None of these

d)

More than one of these

14.

The name for this molecule is:

a)

(cis)-3-methoxyhex-3-ene

b)

(Z)-4-methoxyhex-4-ene

c)

(Z)-3-methoxyhex-3-ene

d)

(E)-3-methoxyhex-3-ene