WorksheetsSolving Quadratic Equations (All Methods + Complex Solutions)
Total questions: 17
Worksheet time: 1hrs 4mins
Name
Class
Date
1.
Solve
x2 + 2x - 24 = 0
x2 + 2x - 24 = 0
a)
x = -6, x = 4
b)
x = 6, x = -4
c)
x = 12, x = -2
d)
x = 8, x = -3
2.
Solve the equation using the zero product property.
3x(2x - 4) = 0
a)
x = -1/3 or x = -2
b)
x = 0 or x = 2
c)
x = 0 or x = -2
d)
x = -1/3 or x = 2
3.
Solve
16a2 - 9 = 0
a)
a = -3/4, 3/4
b)
a = -4/3, 4/3
c)
a = 3i/4, -3i/4
d)
a = 3/4
4.
a)
±81
b)
±9
c)
±9i
d)
9
5.
9k2 = -225
a)
5
b)
5i
c)
5i, -5i
d)
-5, 5
6.
a)
A
b)
B
c)
C
d)
D
7.
Solve:
X2 - 3 =6X + 10
a)
X = 26±88
b)
x= 3 ±22
c)
X = −3±22
d)
No Solution
8.
Solve
3a2 - 12a + 12 = 0
3a2 - 12a + 12 = 0
a)
-2
b)
2
c)
2/3
d)
5
9.
(x + 1) 2 = 25
a)
± 5
b)
4 or -6
c)
-4 or 6
d)
± 4
10.
Solve by method of your choice.
x2 + 10x = -9
a)
1 and -12
b)
-1 and -9
c)
1 and -9
d)
1 and -1
11.
If b2-4ac is positive, the quadratic equation has:
a)
Two real solutions that are different
b)
Two imaginary solutions that are different
c)
A real double solution
d)
An imaginary double solution
12.
If b2-4ac is negative, the quadratic equation has:
a)
Two real solutions that are different
b)
Two imaginary solutions that are different
c)
A real double solution
d)
An imaginary double solution
13.
If b2-4ac is 0, the quadratic equation has:
a)
Two real solutions that are different
b)
Two imaginary solutions that are different
c)
A real double solution
d)
An imaginary double solution
14.
What is the discriminant of the quadratic formula?
a)
b2-4a
b)
b2-4ac
c)
b-4ac
d)
b2-ac
15.
Solve x2 - 5x + 10 = 0
a)
(5 - i√15)/2 , (5 + i√15)/2
b)
(5 - √15)/2 , (5 + √15)/2
c)
(5 - i√65)/2 , (5 + i√65)/2
d)
(5 - √65)/2 , (5 + √65)/2
16.
Solve -2x2 + 4x = 9
a)
(2 - i√14)/2 , (2 + i√14)/2
b)
(2 - i√-56)/2 , (2 + i√-56)/2
c)
(2 - i√-14)/2 , (2 + i√-14)/2
d)
(2 - √14)/2 , (2 + √14)/2
17.
Solve for x:
a)
x = {-4, -1}
b)
x = {-1, -4}
c)
x = {2+i, 2-i}
d)
x = {-2+i, -2-i}
100 %
