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IMPLICIT AND PARAMETRIC DIFFERENTIATION

Total questions: 12

Worksheet time: 44mins

Name
Class
Date
1.
Find dy/dx by Implicit Differentiation 
x3 +y3  = 36
a)
6 -x
b)
3x2 +3y2 
c)
−x2/y2
d)
0
2.
Find dy/dx
xy+y2=2
a)
-y/(x+2y)
b)
y/(x+2y)
c)
-3y/x
d)
-3x/y
3.
Find the derivative:
y=5x2e3x
a)
y'=10xe3x(2x+3)
b)
y'=5xe3x(3x+2)
c)
y'=10ex3x(3x+2)
d)
y'=5xe3x(2x+3)
4.
Find the second derivative of f(x) = x+ e - cosx
a)
f"(x) = 2 + ex + cosx
b)
f"(x) = 2x + ex + cosx
c)
f"(x) = 2x + xex - cosx
d)
f"(x) = 2x + ex + sinx
5.

Find dy/dx at the given point


x3 +2xy -y2=11 at (2,3)

a)

-4/7

b)

12

c)

-9

d)

9

6.

Find   dydx\frac{dy}{dx}  :  2x23y2=42x^2-3y^2=4  

a)

 2xy\frac{2x}{y}  

b)

 x3y\frac{x}{3y}  

c)

 3y2x\frac{3y}{2x}  

d)

 2x3y\frac{2x}{3y}  

7.

Find the derivative of  x2+xy+y3=0x^2+xy+y^3=0  

a)

  2x1+3y2-\ \frac{2x}{1+3y^2}  

b)

 x+3y22x+y-\frac{x+3y^2}{2x+y}  

c)

 2x+yx+3y2-\frac{2x+y}{x+3y^2}  

d)

 2xx+3y2-\frac{2x}{x+3y^2}  

8.

Find the point based on the parametric equations. t = 3

x = 1 - 2t

y =4t + 1

a)

(-5, 13)

b)

(13, -5)

c)

(5, 13)

d)

(13, 5)

9.

Find the ordered pair based on the parametric equations.

t = -2

x = t2 - 2

y = -t + 2

a)

(2, 4)

b)

(4, 2)

c)

(-6, 0)

d)

(0,-6)

10.

For x=3t2+1, y=t32t2x=3t^2+1,\ y=t^3-2t^2 , determine  d2ydx2\frac{d^2y}{dx^2}  in terms of t. 


a)

 d2ydx2=112t\frac{d^2y}{dx^2}=-\frac{1}{12t}  

b)

 d2ydx2=112\frac{d^2y}{dx^2}=\frac{1}{12}  

c)

 d2ydx2=112t\frac{d^2y}{dx^2}=\frac{1}{12t}  

d)

 d2ydx2=1t\frac{d^2y}{dx^2}=-\frac{1}{t}  

11.

For x=12t2+2, y=sin(t+1)x=\frac{1}{2}t^2+2,\ y=\sin\left(t+1\right) , determine  d2ydx2\frac{d^2y}{dx^2}  in terms of t. 


a)

 d2ydx2=tcos(t+1)+sin(t+1)t3\frac{d^2y}{dx^2}=\frac{t\cos\left(t+1\right)+\sin\left(t+1\right)}{t^3}  

b)

 d2ydx2=tcos(t+1)sin(t+1)t3\frac{d^2y}{dx^2}=\frac{-t\cos\left(t+1\right)-\sin\left(t+1\right)}{t^3}  

c)

 d2ydx2=tsin(t+1)+cos(t+1)t3\frac{d^2y}{dx^2}=\frac{t\sin\left(t+1\right)+\cos\left(t+1\right)}{t^3}  

d)

 d2ydx2=tsin(t+1)cos(t+1)t3\frac{d^2y}{dx^2}=\frac{-t\sin\left(t+1\right)-\cos\left(t+1\right)}{t^3}  

12.

For x=et, y=t3+t+1x=e^{-t},\ y=t^3+t+1 , determine  d2ydx2\frac{d^2y}{dx^2}  in terms of t. 


a)

 d2ydx2=(3t2+6t+1)e2t\frac{d^2y}{dx^2}=\left(3t^2+6t+1\right)e^{2t}  

b)

 d2ydx2=(t2+6t+1)e2t\frac{d^2y}{dx^2}=\left(t^2+6t+1\right)e^{2t}  

c)

 d2ydx2=(3t2+6t+1)et\frac{d^2y}{dx^2}=\left(3t^2+6t+1\right)e^t  

d)

 d2ydx2=(t2+t+1)e2t\frac{d^2y}{dx^2}=\left(t^2+t+1\right)e^{2t}