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WorksheetsKepler's law
Total questions: 15
Worksheet time: 8mins
From Kepler’s law of orbit, we can infer that the sun is located _____ of the planet’s orbit.
at the center
at one of the foci
at both foci
anywhere along the semi-minor axis
What does Kepler’s law of period relate?
Time period and semi-minor axis
Time period and eccentricity
Time period and semi-major axis
Time period and area swept by the planet
In the figure shown, what is the point “A” called?
perihelion
aphelion
foci
center
In the figure shown, what is the point “B” called?
Perihelion
Aphelion
Foci
Center
Kepler’s laws of planetary motion improved ______
the heliocentric theory
the geocentric theory
the big bang theory
the string theory
Kepler's second law simply means that _________.
a planet moves more rapidly when near the Sun than when farther away
planets close to the Sun have shorter periods than those farther away
the Sun is at the center of planetary orbits
slowly moving planets are close to the Sun
Kepler's third law is used to estimate ______ of objects by measuring ______.
the masses; their periods and orbital sizes
the period; their masses and orbital sizes
the orbital size; their periods and masses
the period; their masses
The time taken by a planet to cover an area of 1 million square km is 36 hours. What is the time taken by the same planet to sweep an area of 2 million square km?
18 hours
36 hours
72 hours
144 hours
The time taken by a planet to cover an area of 2 million square km is 72 hours. What is the time taken by the same planet to sweep an area of 3 million square km?
18 hours
36 hours
72 hours
108 hours
The time taken by a planet to cover an area of 3 million square km is 108 hours. What is the time taken by the same planet to sweep an area of 2 million square km?
18 hours
36 hours
72 hours
108 hours
The two planets orbit around the sun with orbital radii R1=R and R2=4R respectively. The ratio of their periods T1/T2 around the sun is ___.
1/16
1/8
1/4
1/2
If the distance from the earth to the sun was only one-quarter of the current distance, the time of one year would have been ___.
1/2 year
1/4 year
1/8 year
1/16 year
A planet in orbit around it. When the planet is about R from the sun, its velocity is v. Calculate the speed at the point it is about 4R from the sun.
v/4
4v
v/2
2v
Star X has twice the mass of the Sun. One of Star X’s planets has the same mass as the Earth, and orbits Star X at the same distance at which the Earth orbits the Sun. The orbital speed of this planet of Star X is ________.
faster than the Earth’s orbital speed.
the same as the Earth’s orbital speed.
slower than the Earth’s orbital speed.
not enough information given to decide
Suppose the Sun were to shrink to half of its present radius while maintaining the same mass. What effect would this have on the Earth’s orbit?
The size of the orbit would decrease and the orbital period would decrease.
The size of the orbit would increase and the orbital period would increase.
The size of the orbit and the orbital period would remain unchanged.
none of these.
