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CHAP 9: DIFFERENTIATION (KMS)

Total questions: 63

Worksheet time: 1hrs 3mins

Name
Class
Date
1.

Given y=3ex4, y=3e^{x^4},\  then dydx=p×3ex4\frac{\text{d}y}{\text{d}x}=p\times3e^{x^4}  .What is p?p?  

a)

x4x^4  

b)

4x34x^3  

c)

12x312x^3  

d)

12x412x^4  

2.

Given y=2ex2+1.y=2e^{x^2+1}.  Then, ddx(2ex2+1)=p×2ex2+1\frac{d}{dx}\left(2e^{x^2+1}\right)=p\times2e^{x^2+1}  . Which fits the role of p?p?  

a)

4x4x  

b)

44  

c)

22  

d)

2x2x  

3.

Given y=ex,y=e^{\sqrt[]{x}},  then y' is pexpe^{\sqrt[]{x}}  . What is p?p?  

a)

x\sqrt[]{x}  

b)

2x2\sqrt[]{x}  

c)

12x\frac{1}{2}\sqrt[]{x}  

d)

12x\frac{1}{2\sqrt[]{x}}  

4.

y=21−3xy=2^{1-3x}  . Then, dydx=21−3x ln⁡a ×b\frac{\text{d}y}{\text{d}x}=2^{1-3x}\ \ln a\ \times b  .

What are the CORRECT values of a,b?a,b?  

a)

a=2,b=3a=2,b=3  

b)

a=3,b=2a=3,b=2  

c)

a=2,b=−3a=2,b=-3  

d)

a=−3,b=2a=-3,b=2  

5.

Given y=2e3x−7xy=2e^{3x}-7^x  . Then, dydx=pe3x−7xln⁡q.\frac{\text{d}y}{\text{d}x}=pe^{3x}-7^x\ln q.  

What satisfies p,q?p,q?  

a)

p=2,q=xp=2,q=x  

b)

p=3,q=7p=3,q=7  

c)

p=6,q=xp=6,q=x  

d)

p=6,q=7p=6,q=7  

6.

Given y=2xe3x.y=2xe^{3x}.  Then, dydx=pe3x+2x(q).\frac{\text{d}y}{\text{d}x}=pe^{3x}+2x\left(q\right).  

Which BEST represents p,q?p,q?  

a)

p=2,q=e3xp=2,q=e^{3x}  

b)

p=3,q=e3xp=3,q=e^{3x}  

c)

p=2,q=3e3xp=2,q=3e^{3x}  

d)

p=3,q=3e3xp=3,q=3e^{3x}  

7.

ddx(x−1e2x)=e2x(1)−(x−1)(e2x)(e2x)2\frac{\text{d}}{\text{d}x}\left(\frac{x-1}{e^{2x}}\right)=\frac{e^{2x}\left(1\right)-\left(x-1\right)\left(e^{2x}\right)}{\left(e^{2x}\right)^2}  .

It is believed there is AN ERROR in the above working. If yes, which term?

a)

e2x(1)e^{2x}\left(1\right)  

b)

(x−1)e2x\left(x-1\right)e^{2x}  

c)

(e2x)2\left(e^{2x}\right)^2  

d)

Impossible, all is OK

8.

Given y=(1−e2x)3,y=\left(1-e^{2x}\right)^3,  then dydx=3(1−e2x)2(−e2x).\frac{\text{d}y}{\text{d}x}=3\left(1-e^{2x}\right)^2\left(-e^{2x}\right).  

There is A MISTAKE in one of the terms. What is the MISTAKE?

a)

33  

b)

(1−e2x)\left(1-e^{2x}\right)  

c)

(1−e2x)2\left(1-e^{2x}\right)^2  

d)

−e2x-e^{2x}  

9.

Given y=73x,y=7^{3x},  then dydx=73x(ln⁡ a)b.\frac{\text{d}y}{\text{d}x}=7^{3x}\left(\ln\ a\right)b.  

What is a?a?  

a)

33  

b)

3x3x  

c)

77  

d)

73x7^{3x}  

10.

Given y=73x,y=7^{3x},  then dydx=73x(ln⁡ a)b.\frac{\text{d}y}{\text{d}x}=7^{3x}\left(\ln\ a\right)b.  

What is b?b?  

a)

33  

b)

3x3x  

c)

77  

d)

73x7^{3x}  

11.

Given y=5x2.y=5^{x^2}.  Then, dydx=5x2ln⁡5 ddx(q)\frac{\text{d}y}{\text{d}x}=5^{x^2}\ln5\ \frac{\text{d}}{\text{d}x}\left(q\right)  .

What is q?q?  

a)

55  

b)

x2x^2  

c)

11  

d)

2x2x  

12.

Given y=ln⁡(2x),y=\ln\left(2x\right),  

dydx=?\frac{\text{d}y}{\text{d}x}=?  

a)

12x\frac{1}{2x}  

b)

1x\frac{1}{x}  

c)

ln⁡2x\ln2x  

d)

ln⁡2\ln2  

13.

y=2sin⁡x−3cot⁡xy=2\sin x-3\cot x  

ddx(y)=ddx(2sin⁡ x)−ddx(3 cot⁡ x)\frac{d}{dx}\left(y\right)=\frac{d}{dx}\left(2\sin\ x\right)-\frac{d}{dx}\left(3\ \cot\ x\right)  

p=q+rp=q+r  

What is p?p?  

a)

11  

b)

yy  

c)

dydx\frac{\text{d}y}{\text{d}x}  

d)

dxdy\frac{\text{d}x}{\text{d}y}  

14.

y=2sin⁡x−3cot⁡xy=2\sin x-3\cot x  

ddx(y)=ddx(2sin⁡ x)−ddx(3 cot⁡ x)\frac{d}{dx}\left(y\right)=\frac{d}{dx}\left(2\sin\ x\right)-\frac{d}{dx}\left(3\ \cot\ x\right)  

p=q+rp=q+r  

What is q?q?  

a)

2sin⁡ x2\sin\ x  

b)

−2cos⁡ x-2\cos\ x  

c)

cos x\text{cos x}  

d)

2cos⁡x\text{}2\cos x  

15.

y=2sin⁡x−3cot⁡xy=2\sin x-3\cot x  

ddx(y)=ddx(2sin⁡ x)−ddx(3 cot⁡ x)\frac{d}{dx}\left(y\right)=\frac{d}{dx}\left(2\sin\ x\right)-\frac{d}{dx}\left(3\ \cot\ x\right)  

p=q+rp=q+r  

What is r?r?  

a)

−3cosec⁡2x-3\operatorname{cosec}^2x  

b)

cosec⁡2x\operatorname{cosec}^2x  

c)

3cosec⁡2x3\operatorname{cosec}^2x  

d)

−cosec⁡2x-\operatorname{cosec}^2x  

16.

Given y=cos⁡ 4x.y=\cos\ 4x.  Then, y′=4sin⁡ 4xy'=4\sin\ 4x  .

It was realized the value of 44  is INCORRECT. What is the CORRECT value?

a)

11  

b)

−1-1  

c)

−4-4  

d)

Disagree.It is indeed correct

17.

If y=−4tan⁡x−3sec⁡4x,y=-4\tan x-3\sec4x,  then

ddx(−4tan⁡x−3sec⁡4x)=asec⁡2x+bsec⁡4xtan⁡4x\frac{d}{dx}\left(-4\tan x-3\sec4x\right)=a\sec^2x+b\sec4x\tan4x  .

What is a,b?a,b?  

a)

a=4,b=3a=4,b=3  

b)

a=−4,b=−3a=-4,b=-3  

c)

a=−4,b=12a=-4,b=12  

d)

a=−4,b=−12a=-4,b=-12  

18.

Given y=cot⁡ 7x, dydx=a cosec⁡2 7xy=\cot\ 7x,\ \frac{dy}{dx}=a\ \operatorname{cosec}^2\ 7x  .

What is a?a?  

a)

11  

b)

−1-1  

c)

77  

d)

−7-7  

19.

Given y=2cos⁡34x. y=2\cos^34x.\  Then, y=2(cos⁡4x)3y=2\left(\cos4x\right)^3  .

Given dydx=6(cos⁡4x)2(sin⁡4x)\frac{\text{d}y}{\text{d}x}=6\left(\cos4x\right)^2\left(\sin4x\right)  .

Which is INCORRECT term?

a)

66  

b)

cos⁡4x\cos4x  

c)

(cos⁡4x)2\left(\cos4x\right)^2  

d)

(sin⁡4x)\left(\sin4x\right)  

20.

Given y=sin⁡24xy=\sin^24x  .

Then, dydx=2(sin⁡4x)q\frac{\text{d}y}{\text{d}x}=2\left(\sin4x\right)q  .

What is q?q?  

a)

cos⁡4x\cos4x  

b)

−cos⁡4x-\cos4x  

c)

4cos⁡4x4\cos4x  

d)

−4cos⁡4x-4\cos4x  

21.

Given y=3tan⁡22x.y=3\tan^22x.  

Then, dydx=6(tan⁡2x)q\frac{\text{d}y}{\text{d}x}=6\left(\tan2x\right)q  .What is q?q?  

a)

sec⁡22x\sec^22x  

b)

−sec⁡22x-\sec^22x  

c)

2sec⁡22x2\sec^22x  

d)

−2sec⁡22x-2\sec^22x  

22.

ddx(sin⁡xcos⁡x)=(cos⁡x)p−sin⁡x(q)r\frac{d}{dx}\left(\frac{\sin x}{\cos x}\right)=\frac{\left(\cos x\right)p-\sin x\left(q\right)}{r}  .

What is p?p?  

a)

sin⁡x\sin x  

b)

−sin⁡x-\sin x  

c)

cos⁡ x\cos\ x  

d)

−cos⁡x-\cos x  

23.

ddx(sin⁡xcos⁡x)=(cos⁡x)p−sin⁡x(q)r\frac{d}{dx}\left(\frac{\sin x}{\cos x}\right)=\frac{\left(\cos x\right)p-\sin x\left(q\right)}{r}  .

What is q?q?  

a)

sin⁡x\sin x  

b)

−sin⁡x-\sin x  

c)

cos⁡ x\cos\ x  

d)

−cos⁡x-\cos x  

24.

ddx(sin⁡xcos⁡x)=(cos⁡x)p−sin⁡x(q)r2\frac{d}{dx}\left(\frac{\sin x}{\cos x}\right)=\frac{\left(\cos x\right)p-\sin x\left(q\right)}{r^2}  .

What is r?r?  

a)

sin⁡x\sin x  

b)

−sin⁡x-\sin x  

c)

cos⁡ x\cos\ x  

d)

−cos⁡x-\cos x  

25.

Given y=ln⁡((x3+1)(1−2x2)).y=\ln\left(\left(\sqrt[]{x^3+1}\right)\left(1-2x^2\right)\right).  

Which shows the CORRECT use of law of log to ensure READY to find dydx\frac{\text{d}y}{\text{d}x}  ?

a)

y=ln⁡x3+1+ln⁡(1−2x2)3y=\ln\sqrt[]{x^3+1}+\ln\left(1-2x^2\right)^3  

b)

y=ln⁡x3+1+3ln⁡(1−2x2)y=\ln\sqrt[]{x^3+1}+3\ln\left(1-2x^2\right)^{ }

c)

y=2ln⁡(x3+1)+3ln⁡(1−2x2)y=2\ln\left(x^3+1\right)+3\ln\left(1-2x^2\right)^{ }

d)

y=12ln⁡(x3+1)+3ln⁡(1−2x2)y=\frac{1}{2}\ln\left(x^3+1\right)+3\ln\left(1-2x^2\right)^{ }

26.

y=12ln⁡(x3+1)+3ln⁡(1−2x2)y=\frac{1}{2}\ln\left(x^3+1\right)+3\ln\left(1-2x^2\right)  

dydx=12(ab)+3(cd)\frac{dy}{dx}=\frac{1}{2}\left(\frac{a}{b}\right)+3\left(\frac{c}{d}\right)  

What is a?a?  

a)

11  

b)

3x23x^2  

c)

x3x^3  

d)

x3+1x^3+1  

27.

y=12ln⁡(x3+1)+3ln⁡(1−2x2)y=\frac{1}{2}\ln\left(x^3+1\right)+3\ln\left(1-2x^2\right)  

dydx=12(ab)+3(cd)\frac{dy}{dx}=\frac{1}{2}\left(\frac{a}{b}\right)+3\left(\frac{c}{d}\right)  

What is b?b?  

a)

11  

b)

3x23x^2  

c)

x3x^3  

d)

x3+1x^3+1  

28.

y=12ln⁡(x3+1)+3ln⁡(1−2x2)y=\frac{1}{2}\ln\left(x^3+1\right)+3\ln\left(1-2x^2\right)  

dydx=12(ab)+3(cd)\frac{dy}{dx}=\frac{1}{2}\left(\frac{a}{b}\right)+3\left(\frac{c}{d}\right)  

What is c?c?  

a)

11  

b)

4x4x  

c)

−4x-4x  

d)

1−2x21-2x^2  

29.

y=12ln⁡(x3+1)+3ln⁡(1−2x2)y=\frac{1}{2}\ln\left(x^3+1\right)+3\ln\left(1-2x^2\right)  

dydx=12(ab)+3(cd)\frac{dy}{dx}=\frac{1}{2}\left(\frac{a}{b}\right)+3\left(\frac{c}{d}\right)  

What is d?d?  

a)

11  

b)

4x4x  

c)

−4x-4x  

d)

1−2x21-2x^2  

30.

Given y=3xln⁡2x.y=3x\ln2x.  

Then, dydx=3ln⁡2x+b\frac{dy}{dx}=3\ln2x+b  .

What is b?b?  

a)

32\frac{3}{2}  

b)

33  

c)

00  

d)

3x\frac{3}{x}  

31.

Given y=ln⁡(x2(1−2x)2x+1).y=\ln\left(\frac{x^2\left(1-2x\right)}{2x+1}\right).  

Choose the form which is READY for differentiation

a)

y=ln⁡x2(1−2x)−ln⁡(2x+1)y=\ln x^2\left(1-2x\right)-\ln\left(2x+1\right)  

b)

y=ln⁡x2+ln⁡(1−2x)−ln⁡(2x+1)y=\ln x^2+\ln\left(1-2x\right)-\ln\left(2x+1\right)  

c)

y=2ln⁡x+ln⁡(1−2x)−ln⁡(2x+1)y=2\ln x+\ln\left(1-2x\right)-\ln\left(2x+1\right)  

d)

y=2ln⁡x+ln⁡(1−2x)+ln⁡(2x+1)y=2\ln x+\ln\left(1-2x\right)+\ln\left(2x+1\right)  

32.

Given y=ln⁡(x+2x−33)y=\ln\left(\frac{\sqrt[]{x+2}}{\sqrt[3]{x-3}}\right)  .

Choose the form which is READY for differentiation.

a)

y=2ln⁡(x+2)−3ln⁡(x−3)y=2\ln\left(x+2\right)-3\ln\left(x-3\right)  

b)

y=ln⁡x+2−ln⁡x−33y=\ln\sqrt[]{x+2}-\ln\sqrt[3]{x-3}  

c)

y=12ln⁡(x+2)−13ln⁡(x−3)y=\frac{1}{2}\ln\left(x+2\right)-\frac{1}{3}\ln\left(x-3\right)  

d)

y=12ln⁡(x+2)−12ln⁡(x−3)y=\frac{1}{2}\ln\left(x+2\right)-\frac{1}{2}\ln\left(x-3\right)  

33.

ddx(ln⁡(1−2x))=a1−2x\frac{d}{dx}\left(\ln\left(1-2x\right)\right)=\frac{a}{1-2x}  .

What is the value of a?a?  

a)

11  

b)

22  

c)

−1-1  

d)

−2-2  

34.

ln⁡y=ln⁡x\ln y=\ln x  

ddx(ln⁡y)=ddx(ln⁡x)\frac{d}{dx}\left(\ln y\right)=\frac{d}{dx}\left(\ln x\right)  

p=rp=r  .

What is p?p?  

a)

11  

b)

1y\frac{1}{y}  

c)

1y(dydx)\frac{1}{y}\left(\frac{dy}{dx}\right)  

d)

dydx\frac{dy}{dx}  

35.

ln⁡y=ln⁡x\ln y=\ln x  

ddx(ln⁡y)=ddx(ln⁡x)\frac{d}{dx}\left(\ln y\right)=\frac{d}{dx}\left(\ln x\right)  

p=rp=r  .

What is r?r?  

a)

11  

b)

1x\frac{1}{x}  

c)

ln⁡ x\ln\ x  

d)

1ln⁡x\frac{1}{\ln x}  

36.

Given ddx(3ln⁡x−2ln⁡(2−3x))=3x−62−3x\frac{d}{dx}\left(3\ln x-2\ln\left(2-3x\right)\right)=\frac{3}{x}-\frac{6}{2-3x}  .

There is a term which is INCORRECT. Which one?

a)

33  

b)

xx  

c)

−6-6  

d)

2−3x2-3x  

37.

ddx(x3+y3)=ddx(sin⁡ x +cos⁡ y)\frac{d}{dx}\left(x^3+y^3\right)=\frac{d}{dx}\left(\sin\ x\ +\cos\ y\right)  

3x2+3y2p=cos⁡x+q3x^2+3y^2p=\cos x+q  

Which represents p,qp,q  CORRECTLY?

a)

p=1,q=−sin⁡ydydxp=1,q=-\sin y\frac{\text{d}y}{\text{d}x}  

b)

p=dydx,q=sin⁡yp=\frac{dy}{dx},q=\sin y  

c)

p=1,q=sin⁡yp=1,q=\sin y  

d)

p=dydx,q=−sin⁡ydydxp=\frac{dy}{dx},q=-\sin y\frac{\text{d}y}{\text{d}x}  

38.

Choose the BEST method to perform differentiation for below.

y=sin⁡2xy=\sin2x  

a)

Product Rule

b)

Quotient rule

c)

Power rule

d)

Chain rule

39.

Choose the BEST method to perform differentiation for below.

y=13sin⁡2xy=\frac{1}{3}\sin2x  

a)

Product Rule

b)

Quotient rule

c)

Power rule

d)

Chain rule

40.

Choose the BEST method to perform differentiation for below.

y=x3sin⁡xy=\frac{x}{3}\sin x  

a)

Product Rule

b)

Quotient rule

c)

Power rule

d)

Chain rule

41.

Choose the BEST method to perform differentiation for below.

y=sin⁡3xy=\sin^3x  

a)

Product Rule

b)

Quotient rule

c)

Power rule

d)

Chain rule

42.

Choose the BEST method to perform differentiation for below.

y=sin⁡xcos⁡xy=\sin^{ }x\cos x  

a)

Product Rule

b)

Quotient rule

c)

Power rule

d)

Chain rule

43.

Choose the BEST method to perform differentiation for below.

y=sin⁡x(cos⁡x)y=\sin^{ }x\left(\cos x\right)  

a)

Product Rule

b)

Quotient rule

c)

Power rule

d)

Chain rule

44.

Given

xy+2y=2xy+2y=2  .

What is the technique used to differentiate term xy?xy?  

a)

Product rule

b)

Quotient rule

c)

Direct

d)

Chain rule

45.

Given

(sin⁡2y+2)2+3y=x2\left(\sin2y+2\right)^2+3y=x^2  .

What is the rule to differentiate term (sin⁡2y+2)2?\left(\sin2y+2\right)^2?  

a)

Power and direct

b)

Power and Chain

c)

Power and Power

d)

Direct and Direct

46.

Given exy+sin⁡y=3e^{xy}+\sin y=3  .

What is the rule to differentiate term exy?e^{xy}?  

a)

Direct exponential formula

b)

Direct exponential formula, product rule

c)

Direct exponential formula,chain rule

d)

Direct exponential formula, direct rule

47.

Given 3sec⁡3x−ycos⁡y+3x=13\sec^3x-y\cos y+3x=1  .

What is the BEST rule to differentiate term 3sec⁡3x ?3\sec^3x\ ?  

a)

Direct rule

b)

Power rule

c)

Product rule

d)

Quotient rule

48.

Given 3sec⁡3x−ycos⁡y+3x=13\sec^3x-y\cos y+3x=1  .

What is the BEST rule to differentiate term ycos⁡y ?y\cos y\ ?  

a)

Direct rule

b)

Power rule

c)

Product rule

d)

Quotient rule

49.

Given ddx(y2)=2yq\frac{d}{dx}\left(y^2\right)=2yq  .

What is q?q?  

a)

dydx\frac{dy}{dx}  

b)

11  

c)

y2y^2  

d)

-

50.

yln⁡x=ex−yy\ln x=e^{x-y}  

pln⁡x+y(q)=ddx(x−y)ex−yp\ln x+y\left(q\right)=\frac{d}{dx}\left(x-y\right)e^{x-y}  

pln⁡x+yx=(1−r)ex−yp\ln x+\frac{y}{x}=\left(1-r\right)e^{x-y}  

What is p?p?  

a)

11  

b)

dydx\frac{dy}{dx}  

c)

y2y^2  

d)

yy  

51.

yln⁡x=ex−yy\ln x=e^{x-y}  

pln⁡x+y(q)=ddx(x−y)ex−yp\ln x+y\left(q\right)=\frac{d}{dx}\left(x-y\right)e^{x-y}  

pln⁡x+yx=(1−r)ex−yp\ln x+\frac{y}{x}=\left(1-r\right)e^{x-y}  

What is q?q?  

a)

ln⁡x\ln x  

b)

xx  

c)

1x\frac{1}{x}  

d)

11  

52.

yln⁡x=ex−yy\ln x=e^{x-y}  

pln⁡x+y(q)=ddx(x−y)ex−yp\ln x+y\left(q\right)=\frac{d}{dx}\left(x-y\right)e^{x-y}  

pln⁡x+yx=(1−r)ex−yp\ln x+\frac{y}{x}=\left(1-r\right)e^{x-y}  

What is r?r?  

a)

yy  

b)

11  

c)

xx  

d)

dydx\frac{dy}{dx}  

53.

1y−1x=3\frac{1}{y}-\frac{1}{x}=3  

yp−x−1=3y^p-x^{-1}=3  

−y−2q+x−2=0-y^{-2}q+x^{-2}=0  

What is p?p?  

a)

−1-1  

b)

−2-2  

c)

00  

d)

11  

54.

1y−1x=3\frac{1}{y}-\frac{1}{x}=3  

yp−x−1=3y^p-x^{-1}=3  

−y−2q+x−2=0-y^{-2}q+x^{-2}=0  

What is q?q?  

a)

11  

b)

x−1x^{-1}  

c)

1x2\frac{1}{x^2}  

d)

dydx\frac{dy}{dx}  

55.

sin⁡ y=ycos⁡ x\sin\ y=y\cos\ x  

adydx=yb+c cos⁡xa\frac{dy}{dx}=yb+c\ \cos x  

What is a?a?  

a)

sin⁡y\sin y  

b)

−sin⁡y-\sin y  

c)

cos⁡y\cos y  

d)

−cos⁡y-\cos y  

56.

sin⁡ y=ycos⁡ x\sin\ y=y\cos\ x  

adydx=yb+c cos⁡xa\frac{dy}{dx}=yb+c\ \cos x  

What is b?b?  

a)

cos⁡x\cos x  

b)

−cos⁡x-\cos x  

c)

sin⁡x\sin x  

d)

−sin⁡x-\sin x  

57.

sin⁡ y=ycos⁡ x\sin\ y=y\cos\ x  

adydx=yb+c cos⁡xa\frac{dy}{dx}=yb+c\ \cos x  

What is c?c?  

a)

11  

b)

dydx\frac{dy}{dx}  

c)

y2y^2  

d)

−1-1  

58.

cos⁡(x+y)=2xsin⁡ y\cos\left(x+y\right)=2x\sin\ y  

−(1+dydx)t=2sin⁡y+cos⁡y dydx-\left(1+\frac{dy}{dx}\right)t=2\sin y+\cos y\ \frac{dy}{dx}  .

Based on above process, t=?t=?  

a)

cos⁡(x+y)\cos\left(x+y\right)  

b)

sin⁡(x+y)\sin\left(x+y\right)  

c)

−cos⁡(x+y)-\cos\left(x+y\right)  

d)

−sin⁡(x+y)-\sin\left(x+y\right)  

59.

Given y=tan⁡(2x),y=\tan\left(2x\right),  

what is dydx=?\frac{\text{d}y}{\text{d}x}=?  

a)

sec⁡2(2x)\sec^2\left(2x\right)  

b)

2sec⁡2(2x)2\sec^2\left(2x\right)  

c)

2x sec⁡2(2x)2x\ \sec^2\left(2x\right)  

d)

−2 sec⁡2(2x)-2\ \sec^2\left(2x\right)  

60.

x=tan⁡yx=\tan y  

ddx(x)=ddx(tan⁡y)\frac{d}{dx}\left(x\right)=\frac{d}{dx}\left(\tan y\right)  

p=qp=q  

What is p?p?  

a)

11  

b)

dydx\frac{dy}{dx}  

c)

dxdy\frac{dx}{dy}  

d)

00  

61.

x=tan⁡yx=\tan y  

ddx(x)=ddx(tan⁡y)\frac{d}{dx}\left(x\right)=\frac{d}{dx}\left(\tan y\right)  

p=qp=q  

What is q?q?  

a)

tan⁡y\tan y  

b)

tan⁡y dydx\tan y\ \frac{dy}{dx}  

c)

sec⁡2y  dydx\sec^2y\ \ \frac{dy}{dx}  

d)

sec⁡2y\sec^2y  

62.

Given

x=tan⁡yx=\tan y  

ddy(x)=ddy(tan⁡y)\frac{d}{dy}\left(x\right)=\frac{d}{dy}\left(\tan y\right)  

p=qp=q  

What is p?p?  

a)

11  

b)

dydx\frac{dy}{dx}  

c)

dxdy\frac{dx}{dy}  

d)

00  

63.

Given

x=tan⁡yx=\tan y  

ddy(x)=ddy(tan⁡y)\frac{d}{dy}\left(x\right)=\frac{d}{dy}\left(\tan y\right)  

p=qp=q  

What is q?q?  

a)

tan⁡ y\tan\ y  

b)

tan⁡ y dydx\tan\ y\ \frac{dy}{dx}  

c)

sec⁡2y dydx\sec^2y\ \frac{dy}{dx}  

d)

sec⁡2y\sec^2y