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AP Chemistry vsepr geometry imf

Total questions: 20

Worksheet time: 39mins

Name
Class
Date
1.
VSEPR stands for ________ theory.
a)
Valence Structure of Electron Pyramids and Regression
b)
Varied Structures of Electrons Paired and Replaced
c)
Varied Shell Energy of Protons and Radiation
d)
Valence Shell Electron Pair Repulsion
2.

Draw the Lewis Dot structure for ICl2- and determine its predicted molecular geometry.

a)

see-saw

b)

trigonal bipyramidal

c)

linear

d)

bent

3.

Draw the Lewis Dot structure for PCl5 and determine the predicted molecular geometry

a)

octahedral

b)

trigonal pyramidal

c)

seesaw

d)

trigonal bipyramidal

4.
Pi bonds are formed by 
a)
side to side overlap of s orbitals
b)
end to end overlap of s orbitals
c)
side to side overlap of p orbitals
d)
end to end overlap of p orbitals
5.

What are the bond angles in this molecule?

a)

all are exactly 90o

b)

all are slightly more than 90o

c)

all are slightly less than 90o

d)

more information is needed

e)

some of the bonds are 90o, others are 120o

6.
This structure is called...
a)
tetrahedral
b)
Trigonal pyramidal
c)
Seesaw
d)
Bent/Angular
7.

The carbon atom undergoes what type of hybridization?

a)

sp hybridization

b)

sp2 hybridization

c)

sp3 hybridization

d)

dsp3 hybridization

8.

The nitrogen atom undergoes what type of hybridization?

a)

sp hybridization

b)

sp2 hybridization

c)

sp3 hybridization

d)

dsp3 hybridization

9.

Determine the VSEPR shape and intermolecular forces that exist between molecules of the given structure.

a)

Square Pyramidal; LDF

b)

Square Pyramidal; LDF and Dipole-Dipole

c)

Octahedral; LDF

d)

Octahedral; LDF and Dipole-Dipole

10.

Identify the hybridization and IMF of the given structure.

a)

sp3d; LDF

b)

sp3d; LDF and Dipole-Dipole

c)

sp3d2; LDF

d)

sp3d2; LDF and Dipole-Dipole

11.

Which best describes the bonding in the cyanide ion (CN-)?

a)

3 (sigma) bonds

b)

2 (sigma) bonds and I (pi) bond

c)

1 (sigma) bond and 2 (pi) bonds

d)

3 (pi) bonds

12.

The effect of lone pairs of electrons on molecular geometry is

a)

to push other atoms closer together because lone pairs are

localized on only one nucleus, so they spread out more.

b)

to allow the other atoms to be further apart because lone pairs

take up less space than bonding pairs.

c)

to create an aysmmetical distribution of the electrons within

the atom, thus creating a polar molecule by creating dipoles.

d)

to help to create resonance structures through the formation of

pi bonds.

13.

Why can a molecule with the structure of NBr5 not exist?

a)

Nitrogen only has two energy levels and is thus unable to expand its octet.

b)

Bromine is much larger than nitrogen and cannot be a terminal atom in this molecule

c)

It is impossible to complete the octets for all six atoms using only valence electrons.

d)

Nitrogen does not have a low enough electronegativity to be the central atom of this molecule.

14.

The molecule that uses sp3d hybrid orbital on the central atom is

a)

BCl3

b)

NCl3

c)

ICl3

d)

PCl3

15.
Which of the following factors plays an important role in the identification of specific intermolecular forces in a molecule?
a)
bond type
b)
density
c)
solubility
d)
molecular polarity
16.
Which of the following molecules contains only London dispersion forces?
a)
CF4
b)
HCl
c)
H2O
d)
MgO(aq)
17.
Which of the following molecules would have the lowest boiling point?
a)
CH4
b)
C2H6
c)
C3H8
d)
C4H10
18.
Which of the following molecules has hydrogen bonding?
a)
HCl
b)
HI
c)
HF
d)
HBr
19.
Hydrocarbons will have which type of intermolecular forces?
a)
Dispersion
b)
dipole
c)
hydrogen bonds
20.
Which noble gas has the highest boiling point?
a)
Xe
b)
Kr
c)
Ar
d)
He