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Is 1296 both a square and a cube?
Yes
No
36+723\sqrt[]{6}+\frac{7}{2}36+27
10.848
5.408
36.303
64+49−52+52\sqrt[]{64}+\sqrt[]{49}-5^2+\frac{5}{2}64+49−52+25 = ? (a)
(x2)−3y=0\sqrt[]{\left(x^2\right)}-3y=0(x2)−3y=0
x=6
y=2
x=9
y=3
x=2
y=1
5!+121−14×2.355!+\sqrt[]{121}-14\times2.355!+121−14×2.35 = ? (a)
{64+52×[14+0.252+(6−4)]}\left\{\sqrt[]{64}+5^2\times\left[\frac{1}{4}+0.25^2+\left(6-4\right)\right]\right\}{64+52×[41+0.252+(6−4)]} (a)
π≈?\pi\approx?π≈?
355113\frac{355}{113}113355
314100\frac{314}{100}100314
227\frac{22}{7}722
1296+52 .?. 61\sqrt[]{1296}+5^2\ .?.\ 611296+52 .?. 61
<
>
=
≥\ge≥
≤\le≤
12+32+52+1+2+3−16−0.64\frac{1}{2}+\frac{3}{2}+\frac{5}{2}+1+2+3-\sqrt[]{16}-\sqrt[]{0.64}21+23+25+1+2+3−16−0.64
5.7
14.5
6.7
~-2.717
10+5−4\sqrt[]{10}+5-410+5−4
~4.162
~-0.127
~7.449
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