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Land survey 2

Total questions: 25

Worksheet time: 13mins

Name
Class
Date
1.

What is the principle of surveying?

a)

Working from part of whole

b)

Working from whole to part

c)

Working from higher to lower.

d)

Working from lower to higher

2.

An offer is measured with an accuracy of 1 in 40 . If the scale of plotting is 1 cm = 30 m, the limiting length of offset, so that the displacement of point on paper from both sources of error many not exceed 0.025 mm, is

a)

21.3 m

b)

21.4 m

c)

21.2 m

d)

21.8 m

3.

The whole circle bearing of S31 36’ E is____

a)

138 24

b)

158 24

c)

128 24

d)

148 24

4.

If the image formed by the objective lens is not in the same plane with cross hairs, then it is known as

a)

Focusing of eye piece

b)

Focusing of objective

c)

Parallax

d)

Aberration

5.

The automatic check for leveling in case of height of instrument method is

a)

𝚺BS — 𝚺FS = Last RL — RL

b)

𝚺BS —𝚺FS = 𝚺Rise — 𝚺fall

c)

𝚺Rise — 𝚺fall = 𝚺last RL — first RL

d)

None of these

6.

A line lying throughout the surface of the ground and preserving a constant inclination to the horizontal is

a)

Contour gradient

b)

Horizontal equivalent

c)

Contour interval

d)

Vertical control

7.

Surveyor’s chain consists of 100 links along a length of

a)

100 ft long

b)

33 ft long

c)

66 ft long

d)

50 ft long

8.

Correction for temperature in a chain when the temperature at field is more than the standard temperature is ______

a)

Additive

b)

Negative

c)

Constant

d)

None of these

9.

In a surveyor’s compass the graduation are in

a)

Whole circle bearing

b)

Quadrantal bearing

c)

Both the circle bearing and quadrantal bearing

d)

None of these

10.

Small scale representation of map is known as

a)

Scale

b)

Plan

c)

Grid

d)

Survey map

11.

The sag correction for a 30 m Steel tap under a pull of 200 N in four equal spans of 8 m each : ( the weight of one cubic cm of Steel = 0.078 N and area of cross- section of the tape =0.08 sqm)

a)

3.9 N

b)

4.2 N

c)

4.99 N

d)

4.6 N

12.

In the leveling between two point A and B on opposite banks of the river, the staff reading A and B were 1.295 and 2.960 m respectively. The level was then removed a set up near B and the reading on A and B were 0.56 and 2.42 . The true difference of levels between A and B is ——————

a)

3.486 m

b)

3.525 m

c)

3.538 m

d)

3.624 m

13.

Co-ordinates

A straight tunnel is to be run between to point A and B whose co- ordinates are as given above .

The length and bearing of CD if D is the mid-point of AB , are

a)

74° 38', 1380.2 m

b)

75° 39', 1278.4 m

c)

78° 34' , 1295.7 m

d)

76° 32', 1287.6 m

14.

The perpendicular offsets at 20 m intervals from survey line to an irregular boundary lines are 3.25, 5.6, 4.2, 6.65, 8.75, 6.2, 3.25, 4.2, 5.65 . The area enclosed between survey line by the application of trapezoidal rule is _____

a)

820 m2

b)

833 m2

c)

860 m2

d)

866 m2

15.

An observation with a theodilite given staff reading of 1.052 and 2.502 for angles of elevation gave 8% and 6% respectively. The vertical angle was 5.25% . The horizontal distance of staff station if the instrument elevation is 942.5 m, is ———

a)

48 m

b)

52 m

c)

56 m

d)

50 m

16.

The following bearing is closed traverse :

The interior angles between the bearings are————

a)

50°, 65.3°, 230.5°, 100°, 123°

b)

50.5°, 138.40°, 131°, 120.40°,99.10°

c)

53°, 48.8°,123.2°,121°, 100.10°

d)

58°, 62.5°,73°,148°,133°

17.

In order to find the difference in the elevation between two points P and Q , a level was set up line PQ; 40 meters from P and 1.280 from Q.

The readings obtained on staff kept at P and Q were 0.525 m and 4.92 m. Respectively. The true difference in elevation between P and Q is——-

a)

3.87 m

b)

4.82 m

c)

4.39 m

d)

4.31 m

18.

Match the following

CODES:

a)

1 – ii, 2 – iii, 3 – i, 4 – iv

b)

1 – iv, 2 – i, 3 – iii, 4 – ii

c)

1 – iii , 2 – i, 3 – ii, 4 – iv

d)

1 – iii, 2 – iv, 3 – ii, 4 – i

19.

A surveyor measured the distance between two points plan drawn to a scale of 1 cm = 30 m and the result was 500 m. Later it’s was discovered that 1 cm =10 m scale was used . The true distance between the points would be ————

a)

168.3 m

b)

165.6 m

c)

162.3 m

d)

166.6 m

20.

I.The durinal variation is the departure of the destination from its mean value a during a period of 24 hours .

2. The variation which has a yearly period is known as annual variation

a)

1 is true

b)

2 is true

c)

Both 1 and 2 are true

d)

Both 1 and 2 are false

21.

Match the following

CODES:

a)

1 – ii, 2 – iii, 3 – i

b)

1 – iii, 2 – ii, 3 – i

c)

1 – ii, 2 –iii, 3 –i

d)

1 –ii, 2 – ii, 3 –iii

22.

Two straight lines intersect at an angle of 50°. The radius of curve joining the two straight lines 400 m.

The length the long chord and mid ordinates in the meters is ———

a)

337.8 m, 36.8 m

b)

340.6 m, 38.3 m

c)

338.09 m, 37.47 m

d)

360.7 m, 35.6 m

23.

During the leveling work along a falling gradient using dumpy level and staff of 3 m length , the following successive readings are taken:

1.623, 2.789, 0.260, 1.520

What will be the direct order of booking these four readings in level book?

a)

BS, FS, BS, FS

b)

BS, IS, FS, FS

c)

BS, IS, IS, FS

d)

BS, IF, BS, FS

24.

The bench mark with reduce leaves (RL) =156.305 m has been established at the floor of a room . It is required to find the RL of the underside of root. Bank sight (BS) is 1.8 m whereas the fore sight (FS) is 0.675, the RL will be———

a)

152.3 m

b)

159.8 m

c)

158.7 m

d)

153.3 m

25.

Assertion (A): Radiation method of plane table survey is employed for locating the details

Reason (R): Radiation method is suitable when distance are small.

a)

A and R are true and R is the correct explanation of A

b)

A and R are true and R is not correct explanation of A

c)

A is true and R is false

d)

A is false and R is true