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WorksheetsUnit 8 Quiz 2 Study Guide
Total questions: 10
Worksheet time: 5mins
Given the thermochemical equation, calculate the heat evolved when 74.6 g of sulfur dioxide (molar mass = 64.07 g/mol) is converted to sulfur dioxide.
-115 kJ
115 kJ
-115.39 kJ
115.39 kJ
Using the thermochemical eq. given, calculate the heat evolved when 266 g of white phosphorus burns in air.
-6.47 x 10^3 kJ
-6468 kJ
6.47 x 10^3 kJ
6468 kJ
The change of enthalpy is usually expressed in___________.
kilojoule
joule
kilogram
newton
ΔH means:
temperature
calorimetry
enthalpy
syntropy
What is the heat in Joules required to convert 25 grams of -10 °C ice into 150 °C steam?
Useful information:
heat of fusion of water = 334 J/g
heat of vaporization of water = 2257 J/g
specific heat of ice = 2.09 J/g·°C
specific heat of water = 4.18 J/g·°C
specific heat of steam = 2.09 J/g·°C
(1) what is the amount of heat required during your first equation raising from -10°C to 0°C.
-522.5 J
522.5 J
1045 J
-1045 J
What is the heat in Joules required to convert 25 grams of -10 °C ice into 150 °C steam?
Useful information:
heat of fusion of water = 334 J/g
heat of vaporization of water = 2257 J/g
specific heat of ice = 2.09 J/g·°C
specific heat of water = 4.18 J/g·°C
specific heat of steam = 2.09 J/g·°C
(2) What is the energy required to change ice into water? ΔHfus DA calculation
8350 J
16700 J
4175 J
12525 J
What is the heat in Joules required to convert 25 grams of -10 °C ice into 150 °C steam?
Useful information:
heat of fusion of water = 334 J/g
heat of vaporization of water = 2257 J/g
specific heat of ice = 2.09 J/g·°C
specific heat of water = 4.18 J/g·°C
specific heat of steam = 2.09 J/g·°C
(3) Liquid, q=mcΔT
15675 J
20900 J
5225 J
10450 J
What is the heat in Joules required to convert 25 grams of -10 °C ice into 150 °C steam?
Useful information:
heat of fusion of water = 334 J/g
heat of vaporization of water = 2257 J/g
specific heat of ice = 2.09 J/g·°C
specific heat of water = 4.18 J/g·°C
specific heat of steam = 2.09 J/g·°C
(4) Boiling, ΔHvap DA calc
28212 J
56425 J
84637 J
42318 J
What is the heat in Joules required to convert 25 grams of -10 °C ice into 150 °C steam?
Useful information:
heat of fusion of water = 334 J/g
heat of vaporization of water = 2257 J/g
specific heat of ice = 2.09 J/g·°C
specific heat of water = 4.18 J/g·°C
specific heat of steam = 2.09 J/g·°C
(5) Gas, q=mcΔT
5225 J
3918 J
1959 J
2612.5 J
What is the heat in Joules required to convert 25 grams of -10 °C ice into 150 °C steam?
What is the total energy from your 5 reactions?
39180 J
58770 J
78360 J
97950 J
