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Zero product property Lesson 7.3

Total questions: 10

Worksheet time: 14mins

Name
Class
Date
1.
In the equation
 (x + 2)(x - 3) = 0, the binomials are called...?
a)
Factors
b)
Products
c)
Multiples
d)
Zeros
2.
Solve for the values of x:
(x + 2)(x - 3) = 0
a)
{ 2, 3 }
b)
{ -2, -3 }
c)
{ 2, 3 }
d)
{ -2, 3 }
3.
Solve for the values of x:
(2x - 1)(x + 4) = 0
a)
{ 1/2, -4 }
b)
 { 1/2, 4 }
c)
{ 2, -4 }
d)
{ -2, 4 }
4.
Solve and find your x-intercepts:
0=x(x - 6)
a)
x=0 and x=-6
b)
x=1 and x=-6
c)
x=0 and x=6
d)
x=6
5.
Solve and find your zeros:
z(z - 15)=0
a)
z=0 and z=15
b)
z=0 and z=-15
c)
z=-15
d)
z=15
6.
Factor
12x + 9
a)
3(4x + 3)
b)
x(12+9)
c)
3(4x - 3)
d)
not factorable
7.

r(r+7)=0r\left(r+7\right)=0  

a)

r=0, r=7r=0,\ r=-7  

b)

r=0, r=7r=0,\ r=7  

c)

r=7r=-7  

d)

r=7r=7  

8.

(7f3)(9f+1)=0\left(7f-3\right)\left(9f+1\right)=0  

a)

f=37, f=19f=\frac{3}{7},\ f=-\frac{1}{9}  

b)

f=37, f=19f=-\frac{3}{7},\ f=\frac{1}{9}  

c)

f=37, f=19f=\frac{3}{7,}\ f=\frac{1}{9}  

d)

f=37, f=19f=-\frac{3}{7},\ f=-\frac{1}{9}  

9.

(2q+1)(q9)=0\left(2q+1\right)\left(q-9\right)=0  

a)

q=12, q=9q=-\frac{1}{2},\ q=9  

b)

q=12, q=9q=\frac{1}{2},\ q=-9  

c)

q=12, q=9q=-\frac{1}{2},\ q=-9  

d)

q=12, q=9q=\frac{1}{2},\ q=9  

10.

Which equation can be solved with the zero product property?

a)

x26x+1=8x^2-6x+1=8

b)

2x(3x1)=102x\left(3x-1\right)=10

c)

(x4)(2x+3)=0\left(x-4\right)\left(2x+3\right)=0

d)

(x2)(x+3)=1\left(x-2\right)\left(x+3\right)=1