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prop z tests and ints

Total questions: 16

Worksheet time: 48mins

Name
Class
Date
1.

Lumber companies dry freshly cut wood in kilns before selling it. A certain percentage of boards develop cracks on their ends during drying. The current drying procedure is known to produce cracks in 16% of boards. The drying supervisor wants to try a new method that she believes will result in a proportion of cracked boards that is less than 16%.

Write the appropriate hypotheses.

a)

Ho: p = 0.16

Ha: p = 0.16

b)

Ho: p = 0.16

Ha: p =/= 0.16

c)

Ho: p = 0.16

Ha: p > 0.16

d)

Ho: p = 0.16

Ha: p < 0.16

2.

The drying supervisor uses the new method on a random sample of 200 boards.  She conducts a hypothesis test on her sample data and gets a p-value of .027. Based on the p-value , was there convincing evidence that the new method is better? Use  α\alpha  = 0.05.

a)

Since our p-value of 0.027 is < α\alpha  , we reject the null hypothesis. We have convincing evidence that the new method is better. 

b)

Since our p-value of 0.027 is >undefined , we fail to reject the null hypothesis. We do not have convincing evidence that the new method is better. 

3.

At the end of the current growing season, the quality inspector took a sample of 50 pineapples and conducted a hypothesis test on the sample data. His test produced a p-value of 0.1317. Based on the p-value, was there convincing evidence that the current pineapples are larger? Use  α\alpha  =0.05. 

a)

Since our p-value of 0.1317 is < α\alpha  , we reject the null hypothesis. We have convincing evidence that the pineapples are larger. 

b)

Since our p-value of 0.1317 is >undefined , we fail to reject the null hypothesis. We do not have convincing evidence that the pineapples are larger. 

4.

Suppose the P-value for a hypothesis test is 0.0304. Using a = 0.05, what is the appropriate conclusion?

a)

a) Reject the null hypothesis

b)

b) Reject the alternative hypothesis

c)

c) Fail to reject the null hypothesis

d)

d) Fail to reject the alternative hypothesis

5.

When p-value is greater than alpha (we use 0.05) we:

a)

Reject Ho

b)

Fail to reject Ha

c)

Fail to reject Ho

d)

Reject Ha

6.

You perform a One-Proportion z-test on your calculator and get a p-value of 0.05121. What do you do?

a)

Reject the null

b)

Fail to reject the null

7.

You perform a One-Proportion z-test on your calculator and get a p-value of 0.04999. What do you do?

a)

Reject the null

b)

Fail to reject the null

8.
A sample of 400 racing cars showed that 80 cars cost over $700,000. What is the 99% confidence interval of the true proportion of cars costing over $700,000?
a)
0.001 < p < 0.005
b)
0.566 < p < 0.693
c)
0.148 < p < 0.252
d)
0.023 < p < 0.045
9.
A recent study of 750 Internet users in Europe found that 35% of Internet users were women.  What is the 95% confidence interval of the true proportion of women in Europe who use the Internet? 
a)
0.321 < p < 0.379
b)
0.316 < p < 0.384
c)
0.309 < p < 0.391
d)
0.305 < p < 0.395
10.
It was found that in a sample of 90 teenage boys, 70% of them have received speeding tickets.  What is the 90% confidence interval of the true proportion of teenage boys who have received speeding tickets? 
a)
(0.621, 0.780)
b)
(0.591, 0.812)
c)
(0.584, 0.830)
d)
(0.615, 0.805)
11.

What is the margin of error for the interval (6.8, 12.9)?

a)

9.85

b)

3.05

c)

3.50

d)

6.8

12.

In a survey of 104 students, it was found that 79 went to the homecoming game this year.


A 99% confidence interval for p is (0.652, 0.868). Interpret this interval.

a)

99% of the time the true proportion of people who went to the homecoming game this year is between 65.2% and 86.6%.

b)

The probability that the population proportion of people who went to the homecoming game this year is between 65.2% and 86.6% is 95%.

c)

Based on this sample, I am 99% confident that the true proportion of people who went to the homecoming game this year is between 65.2% and 86.6%.

d)

99% of all possible intervals calculated this way will capture the true proportion of people who went to the homecoming game this year

13.

Find the critical value, z*, for 91% confidence.

a)

1.70

b)

1.34

c)

0.18

d)

-1.34

14.

Find the critical value, z* for 97%

a)

1.88

b)

2.17

c)

-1.88

d)

-2.17

15.

Which confidence would result in a wider interval (assuming nothing else changed), 91% or 97%?

a)

97%, z* is larger for higher confidence intervals

b)

97%, the standard error is larger for higher confidence intervals

c)

91%, z* is larger for lower confidence intervals

d)

91%, the standard error is smaller for lower confidence intervals

16.

If we fail to reject the Ho we could potentially be making what type of error?

a)

type 1

b)

type 2

c)

you can't make an error if you fail to reject

d)

The Ho is true