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REVISION CHAPTER 3 & 4 10SC1

Total questions: 10

Worksheet time: 15mins

Name
Class
Date
1.

What is electrolysis?

a)

It is the breakdown of aqueous solutions by using battery

b)

It is to chop chop compounds into two things

c)

It is the decomposition of an ionic compound by the use of electric current

d)

Its electrolysis and using electric

2.

A battery in an electrolytic cell has two terminals, they are:

(tick more than 1)

a)

positive terminal

b)

plus terminal

c)

negative terminal

d)

minus terminal

e)

anode

3.

The anode attracts the anions in the electrolyte. So that means the anode is connected to the:

a)

negative terminal

b)

plus terminal

c)

minus terminal

d)

positive terminal

4.

The ions present in aqueous sodium chloride (NaCl) are sodium ions, (a)   ions, chloride ions and hydroxide ions.

5.

The cations in CONCENTRATED sodium chloride are sodium ions and hydrogen ions. Which cation is more in the electrolyte?

a)

hydrogen ions

b)

sodium ions

6.

The anions in CONCENTRATED sodium chloride are chloride ions and hydroxide ions. Which anion is more in the electrolyte?

a)

chloride ions

b)

hydroxide ions

7.

In copper(II) sulfate solution, the cations are copper(II) ions and hydrogen ions.

Copper(II) ions are preferentially discharged.

We say that in the reactivity series, copper is (a)   reactive than hydrogen.

(a four letter word starting with L)

8.

Which is the correct formula for finding the concentration in mol/dm3?

a)

concentration = number of moles (mol)volume (dm3)concentration\ =\ \frac{number\ of\ moles\ \left(mol\right)}{volume\ \left(dm^3\right)}  

b)

concentration = mass of substance (g)volume (dm3)concentration\ =\ \frac{mass\ of\ subs\tan ce\ \left(g\right)}{volume\ \left(dm^3\right)}  

c)

number of moles =mass of substance (g)molar mass (gmol)number\ of\ moles\ =\frac{mass\ of\ subs\tan ce\ \left(g\right)}{molar\ mass\ \left(\frac{g}{mol}\right)}  

9.

Which is the correct formula for finding the concentration in g/dm3?

a)

concentration = number of moles (mol)volume (dm3)concentration\ =\ \frac{number\ of\ moles\ \left(mol\right)}{volume\ \left(dm^3\right)}  

b)

concentration = mass of substance (g)volume (dm3)concentration\ =\ \frac{mass\ of\ subs\tan ce\ \left(g\right)}{volume\ \left(dm^3\right)}  

c)

number of moles =mass of substance (g)molar mass (gmol)number\ of\ moles\ =\frac{mass\ of\ subs\tan ce\ \left(g\right)}{molar\ mass\ \left(\frac{g}{mol}\right)}  

10.

To convert mol/dm3 to g/dm3, you must ............................... by the molar mass. (Hint, its in your notes from previous lesson Thursday 10 March)

a)

multiply

b)

divide