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Worksheets

Areas and formula

Total questions: 17

Worksheet time: 44mins

Name
Class
Date
1.

What is the correct expression for the area?

a)

12×23×20 cm2\frac{1}{2}\times23\times20\ cm^2

b)

23×20 cm223\times20\ cm^2  

c)

40 ×23 cm240\ \times23\ cm^2  

d)
230 cm
2.
When finding the area of a parallelogram, you should-
a)

Add the base and height, then divide by two

b+h2\frac{b+h}{2}  

b)

Multiply the base and height, then divide by two

b×h2\frac{b\times h}{2}  

c)

Find the sum of the base and height

A = b + h

d)

multiply the base and height

A= b x h

3.

This shape is a

a)

trapezium

one pair parallel sides

b)

triangle 3 sides

c)

rhombus

2 pairs equal parallel sides

d)

I don't know

4.
Multiplying by 1/2 is the same as _________.
a)
Multiplying by 2
b)
Adding by 2
c)
Dividing by 2
d)
Subtracting by 2
5.
how do you find area the of a triangle
a)
A=bh
b)
A=1/2h(b+b)
c)
A=1/2bh
6.

how do you find the area of a kite

a)

12x×y\frac{1}{2}x\times y  

product of the diagonals

b)
A=bh
c)
A=1/2h(b+b)
7.

What is the area of this kite

A=12x×yA=\frac{1}{2}x\times y

a)

28 cm228\ cm^2  

b)

56 cm256\ cm^2  

c)

15 cm15\ cm  

8.
A _______________ is a quadrilateral with two sets of parallel sides.
a)
trapezoid
b)
parallelogram
c)
kite
d)
triangle
9.
Name that shape.
a)

parallelogram

b)
quadrilateral
c)

kite.

d)

trapezium

10.
Which of the following is the formula for finding a square?
a)
A=s2
b)
A=lw
c)
A=1/2bh
d)
Add up all the sides
11.

What is the area of this rectangle?

a)

18m218m^2

b)

9m29m^2

c)

20m220m^2

d)

40m240m^2

12.

What is the area formula for a circle?

a)

A = πr2

b)

A = 2πr

c)

A = √π

13.

What is this the formula for? A=θ360×πr2A=\frac{\theta}{360}\times\pi r^2  

a)

arc length

b)

area of a sector

c)

area of a segment

d)

arc measure

14.

Find the area of the shaded sector of circle . The radius is 6 cm and the central angle is 100°.

a)

A=100360×π×42A=\frac{100}{360}\times\pi\times4^2  

b)

A=260360×π×62A=\frac{260}{360}\times\pi\times6^2  

c)

A=100360×π×62A=\frac{100}{360}\times\pi\times6^2  

15.

Find the area of the sector

a)

A=60360×π×42A=\frac{60}{360}\times\pi\times4^2  

b)

A=260360×π×102A=\frac{260}{360}\times\pi\times10^2  

c)

A=60360×π×102A=\frac{60}{360}\times\pi\times10^2  

16.
2. The figure shows a circle inside a triangle.  Which equation could be used to find the area of the shaded region?
a)
A = ½bh - 2πr
b)
A = πr² - ½bh
c)
A = ½bh - πd
d)
A = ½bh - πr²
17.
6. The figure shows 2 circles inside a trapezoid.
Which procedure should be used to find the area of the shaded region?
a)
Subtract the perimeter of the trapezoid from the area of both circles.
b)
Subtract the circumference of both circles from the area of the trapezoid.
c)
Subtract the area of the trapezoid from the area of both circles.
d)
Subtract the area of both circles from the area of the trapezoid.