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Kichik teshik va naychalardan suyuqliklarning oqib chiqishi

Total questions: 6

Worksheet time: 3mins

Name
Class
Date
1.

Diametrlari bir xil bo‘lgan teshik va naychalarning qaysi birida sarf katta bo‘ladi?

a)

torayuvchi konusli naycha

b)

tashqi silindrik naycha

c)

ichki silindrik naycha

d)

kengayuvchi konusli naycha

2.

Ideal suyuqlikning teshik va naychadan oqib chiqish tezligi qaysi formuladan topiladi?

a)

v=ϕ2gHv=\phi\sqrt[]{2gH}  

b)

v=α2gHv=\alpha\sqrt[]{2gH}  

c)

v=2gHv=\sqrt[]{2gH}  

d)

v=2gv=\sqrt[]{2g}  

3.

Suyuqlikning tirqishdan oqib chiqishida tezlik qaysi formuladan topiladi?

a)

v=ϕ2gHv=\phi\sqrt[]{2gH}  

b)

v=α2gHv=\alpha\sqrt[]{2gH}  

c)

v=2gHv=\sqrt[]{2gH}  

d)

v=2gv=\sqrt[]{2g}  

4.

Suyuqlikning tirqishdan oqib chiqishida sarf koeffitsienti qanday topiladi?

a)

μ=ρν\mu=\frac{\rho}{\nu}  

b)

μ=1α+ξ\mu=\frac{1}{\sqrt[]{\alpha+\xi}}  

c)

μ=αξ\mu=\alpha\xi  

d)

μ=ϕϵ\mu=\phi\epsilon  

5.

Teshik va naychalardan suyuqlik oqib chiqishdagi tezlik koeffitsienti deb nimaga aytiladi?

a)

μ=ρν\mu=\frac{\rho}{\nu}  

b)

ϕ=1α+ξ\phi=\frac{1}{\sqrt[]{\alpha+\xi}}  

c)

v=αξv=\alpha\xi  

d)

ϕ=2gh\phi=\sqrt[]{2gh}  

6.

Teshik va naychalardan oqib chiqadigan suyuqlik sarfi qaysi formula yordamida aniqlanadi?

a)

Q=μω2gHQ=\mu\omega\sqrt[]{2gH}  

b)

Q=ϕϵω2gHQ=\phi\epsilon\omega\sqrt[]{2gH}  

c)

Q=αω2gHQ=\alpha\omega\sqrt[]{2gH}  

d)

Q=μω2(g+Pρg)Q=\mu\omega\sqrt[]{2\left(g+\frac{P}{\rho g}\right)}