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WorksheetsLimits Review
Total questions: 50
Worksheet time: 57mins
x→−1−limf(x)=
3
1
Does Not Exist
-1
x→−1+limf(x)=
3
1
Does Not Exist
-1
x→−1limf(x)=
3
1
Does Not Exist
-1
x→1limf(x)=
-5
1
Does Not Exist
-2
x→−2+limf(x)=
4
3
Does Not Exist
1
x→−2−limf(x)=
4
3
Does Not Exist
1
x→−3limf(x)=
0
1
Does Not Exist
-1
x→0limf(x)=
2
1
Does Not Exist
0
Where is the graph discontinuous?
x = 0 only
x = 3 only
x = 0 and x = 3
The graph is always continuous.
Where are there removable discontinuities?
x = 0 only
x = 3 only
x = 0 and x = 3
There are no removable discontinuities.
Where is the graph discontinuous?
x = -2 and x = 1 only
x = -2 only
x = -3, -2 and 1 only
x = 1 only
Which discontinuities are removable?
x = -2 and x = 1 only
x = -2 only
x = -3, -2 and 1 only
x = 1 only
Find the limit as x approaches -3
0
1
-6
DNE
Find the Limit
0
3
1
DNE
Find the limit as x approaches -1
-1
1
0
DNE
List the horizontal and vertical asymptotes of the function.
x = 3
x = -3
y = -2
y = 2
Find the value of f so that f(x) is continuous at x = -1
3
-3
1
-1
Find where the function is continuous
(-∞,-1)(-1,2)(2,∞)
(-∞,2)(2,∞)
(-∞,∞)
(-∞,2)(2,0)(0,∞)
The function is continuous on [−2, 3] .
True
False
The graph is continuous at
x=4 .True
False
The function is continuous on [−2, 5] .
True
False
The function is continuous on the interval (−∞, ∞) .
True
False
On the interval [-7, 7] where is the function f not continuous?
-2, 2
2
-2
nowhere
Over which interval is the function continuous?
[-6, -1]
[-1, 1]
[1, 6]
None of the Above
Which one of these open intervals is the function discontinuous?
(-5,-4)
(-4,-2)
(-2,0)
(0,1)
A function is continuous on a number if and only if f(c) = lim f(x) as x approaches a number c.
TRUE
FALSE
One of the conditions a function must satisfy to be continuous at x=c is "f(c) must exist"
TRUE
FALSE
Which of the following best describes the continuity at x = 1?
Continuous
Removable Discontinuity
Infinite Discontinuity
Jump Discontinuity
Find the value of b for which g(x) is continuous at x=3.
(a)
Is the above function differentiable at x = 0? Why?
No. The x→0lim x32=0 does not exist.
Yes. The h→0limh((x+h)32−(x)32) exists.
Yes. The h→0limh((x+h)32−(x)32) from the left and the right.
No. The undefineddoesn't exist since the left and right hand limits are not the same.
Is the above function differentiable at
x = 0? Why?
Yes. The derivative would be equal to zero since there is a vertical tangent.
No. The derivative would not exist at x = 0 since there is a vertical tangent.
No. The derivative does not exist since x→0lim x31 does not exist.
Yes since h→0lim h(x+h)31−x31 exists.
If f(x) has a derivative at x = a, then f is continuous at x = a.
True
False
I only
II only
I and II only
I and III only
I, II and III
Given that x→2limf(x)=7 and x→2lim g(x)=9, find x→2limg(x)f(x).
-2
7/9
16
9/7
Find x→0limx−2x2−4x+8 .
0
4
-4
d.n.e.
What is the x→−5lim x+5x2−25 ?
d.n.e.
5
10
-10
Consider the graph of f(x). What is the x→4lim f(x)?
2
1
3
d.n.e.
