WorksheetsSubtopic 2.3 Projectile Motion
Total questions: 10
Worksheet time: 14mins
The path of a projectile motion is
Linear
Parabolic
Constant
Straight
At maximum height, the vertical component of the velocity (Vy) is equal to
Vx = Ux = U cos teta
Vy = 0
Vy = Uy = U sin teta
Vy= Ux-gt
Which of the following angle gives a projectile with maximum range?
0
45
60
90
A ball is thrown upward at an angle 45o from a rooftop. Which physical quantity remain constant?
velocity
impulse
y-component of the acceleration
kinetic energy
what is the speed of the object at point A?
0.57u
0.67u
0.87u
1.07u
sketch the direction of the velocity,V and its components, Vx and Vy at point A.
The y-component of the acceleration, ay is equal to 9.81 ms-2 and is directed downward. True or false?
true
false
the horizontal component of the acceleration, ax is always equal to zero. why?
because the direction of the velocity varies.
because the x-component of the velocity is always constant, ux = vx
because object changes its direction.
because its affected by the action of gravity
based on the figure, which concept is incorrect?
Sy = +300 m
uy = 0
u = ux = 50 ms-1
Sx = Ux. t
based on the figure, which concept is incorrect?
ux = 15 cos 30o
uy = 15 sin 30o
final velocity at the landing point v=vx2+vy2
vy = ux -gt
