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CHEM 1342 Ch 13

Total questions: 12

Worksheet time: 18mins

Name
Class
Date
1.

In a sugar and water solution, some sugar remains undissolved in the water. Which term best describes the solution?

a)

Saturated

b)

Unsaturated

c)

Supersaturated

d)

None of these

2.

Compound X has a solubility of 5.88 g per 100 mL of water. A solution containing 1.47 g in 25 mL of water is _.

a)

Saturated

b)

Unsaturated

c)

Supersaturated

d)

Megasaturated

3.

In which conditions do solids have the greatest solubility? (select 2 conditions)

a)

High temperature

b)

Low temperature

c)

High pressure

d)

Low pressure

e)

Pressure doesn't matter

4.

In which conditions do gases have the greatest solubility? (select 2 conditions)

a)

High temperature

b)

Low temperature

c)

High pressure

d)

Low pressure

e)

Pressure doesn't matter

5.

Select the correct formula for molality.

a)

M = mol soluteL solutionM\ =\ \frac{mol\ solute}{L\ solution}  

b)

m = mol solutekg solutionm\ =\ \frac{mol\ solute}{kg\ solution}  

c)

m = mol solutekg solventm\ =\ \frac{mol\ solute}{kg\ solvent}  

d)

m = mol solutemol solutionm\ =\ \frac{mol\ solute}{mol\ solution}  

6.

What is the Vant Hoff factor (i) of C6H12O6?

a)

2

b)

3

c)

24

d)

1

7.

What is the Vant Hoff factor (i) of NaCl?

a)

1

b)

2

c)

3

d)

4

8.

What is the formula for density?

a)

D = massvolumeD\ =\ \frac{mass}{volume}  

b)

D = molmassD\ =\ \frac{mol}{mass}  

c)

D = molmass percentD\ =\ \frac{mol}{mass\ percent}  

d)

D = molkg solventD\ =\ \frac{mol}{kg\ solvent}  

9.

Which of the following concentration units can vary with temperature?

a)

Mass percent

b)

Molarity

c)

Molality

d)

Mole fraction

10.

Why does ammonia (NH3) dissolve better in H2O than in C8H18?

a)

Ammonia is nonpolar and H2O is nonpolar.

b)

Ammonia can interact with H2O through hydrogen bonding.

c)

Ammonia actually dissolves better in C8H18.

11.

Calculate the boiling point elevation of a 0.650 m solution of fructose (C6H12O6) in water. Kb of water is 0.512°C/m.

a)

100°C

b)

0.837°C

c)

0.333°C

d)

0.666°C

12.

Calculate the freezing point of a solution containing 0.135 mol of a nonelectrolyte solute in 2.50 kg of benzene. Kf of benzene is 5.12°C/m. The freezing point of benzene is 5.5°C.

a)

0.828°C

b)

0.276°C

c)

5.22°C

d)

5.78°C