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f(x)=1xf\left(x\right)=\frac{1}{\sqrt[]{x}}f(x)=x1
3x+C3\sqrt[]{x}+C3x+C
2x+C2\sqrt[]{x}+C2x+C
x+Cx+Cx+C
1x+C\frac{1}{\sqrt[]{x}}+Cx1+C
f(x) =cosx−2x6f\left(x\right)\ =\cos x-2x^6f(x) =cosx−2x6
cosx−6x6+C\cos x-6x^6+C^{ }cosx−6x6+C
sinx+3+C\sin x+3+Csinx+3+C
sinx+2x6+C\sin x+2x^6+Csinx+2x6+C
sinx−2x77+C\sin x-\frac{2x^7}{7}+Csinx−72x7+C
f(x)=2x-1
2x+1+C
2x33−1+C\frac{2x^3}{3}-1+C32x3−1+C
2x2+x+C\frac{2x}{2}+x+C22x+x+C
x2−x+Cx^2-x+Cx2−x+C
f(x)=3x2+2x−1f\left(x\right)=3x^2+2x-1f(x)=3x2+2x−1
3x3+2x2−1+C3x^3+2x^2-1+C3x3+2x2−1+C
6x+x2+1+C6x+x^2+1+C6x+x2+1+C
x3+x2−x+Cx^3+x^2-x+Cx3+x2−x+C
x2+2x−1+Cx^2+2x-1+Cx2+2x−1+C
f(x)=1cos2xf\left(x\right)=\frac{1}{\cos^2x}f(x)=cos2x1
tg2x+Ctg^2x+Ctg2x+C
ctgx+C\operatorname{ctg}x+Cctgx+C
tgx+C
cos2x+C\cos^2x+Ccos2x+C
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10 questions
Tema 1 Subtema 1 Pembelajaran 1
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