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3rd form Michaelmas half term revision quiz

Total questions: 79

Worksheet time: 2hrs 47mins

Name
Class
Date
1.

What are the lower bound and upper bound of 62 kg, measured to the nearest kg?

a)

61kg and 63kg

b)

61.5kg and 62.49kg

c)

61.5kg and 62.5kg

d)

61.4kg and 62.6kg

2.

The sides of an equilateral triangle are 9.4 cm, correct to the nearest millimetre.

Work out the upper bound of the perimeter of this triangle.

(a)  

3.

A rectangular field has a length of 9 m and a width of 11 m.

Length are measured to the nearest metre.

What is the greatest possible area of the field?

(a)  

4.

The horsepower of a car is measured at 351 bhp to the nearest integer. What are the limits of accuracy for the actual horsepower?

a)

350.5≤x≤351.5

b)

350.5<x<351.5

c)

350.5<x≤351.5

d)

350.5≤x<351.5

5.

To 1 significant figure 80,000 people attended Manchester United's last game. What is the maximum number of people that could have actually attended the game?

a)

85,000

b)

84,900

c)

84,990

d)

84,999

6.

A car is stopped for speeding travelling at 85mph to the nearest 5mph. What is the slowest speed it could have been doing?

a)

84.5

b)

80

c)

84

d)

82.5

7.

What inequality is graphed?

a)

2 < x ≤ -3

b)

2 < x < -3

c)

x > 2 or x ≤ -3

d)

x > 2 or x < -3

8.

Select the correct inequality for the graph.

a)

-1 ≤ x < 6

b)

1 ≤ x < 6

c)

1 < x ≤ 6

d)

x ≤ 1 or x > 6

9.

-2 < x - 9 < 3

a)

x < 12

b)

7 < x

c)

7 < x < 12

d)

x > 7 or x < 12

10.
a)

F

b)

G

c)

H

d)

J

11.
a)

F

b)

G

c)

H

d)

J

12.
a)

A

b)

B

c)

C

d)

D

13.

Bella has 32 songs on her iphone. Three-eighths of those songs are by Justin Timberlake. How many Justin Timberlake songs does Bella have on her iphone?

a)

12 songs

b)

15 songs

c)

9 songs

d)

18 songs

14.
There are 28 students in a math class. ⁴⁄₇ of the students were boys. How many boys were in the math class?
a)
16 boys
b)
12 girls
c)
14 girls
d)
12 boys
15.
a)
1/5 x 8 = 8/5
b)
2/5 x 8 = 16/5
c)
1/5 x 4 = 4/5
d)
2/5 + 4 = 6/5
16.
Find the product:
a)
9/24
b)
9/28
c)
6/32
d)
1/28
17.

12÷23\frac{1}{2}\div\frac{2}{3}  

a)

12×23\frac{1}{2}\times\frac{2}{3}  

b)

21×23\frac{2}{1}\times\frac{2}{3}  

c)

12×32\frac{1}{2}\times\frac{3}{2}  

d)

21×32\frac{2}{1}\times\frac{3}{2}  

18.
a)

640\frac{6}{40}

b)

34\frac{3}{4}

c)

12\frac{1}{2}

d)

35\frac{3}{5}

19.
Is this a correct answer?
a)
Yes, the student correctly added.
b)
No, you cannot add unlike denominators
c)
No, 5 + 7 is not 12
d)
No, 2 + 3 is not 5
20.
What is the first step in solving this problem? 
⅘ + ½ =
a)
Add the top parts of the fraction
b)
Rewrite the fractions in the simplest form. 
c)
Find a common denominator. 
d)
Make each fraction into an improper faction. 
21.

5/12 + 1/3

a)

6/12

b)

9/12

c)

6/15

d)

3/4

22.
Find the sum.
1/2 + 2/5
a)
3/7
b)
3/10
c)
9/10
d)
1  1/10
23.

6 25\frac{2}{5}  - 2 13\frac{1}{3}   =

a)

4 35\frac{3}{5}  

b)

4 23\frac{2}{3}  

c)

4 115\frac{1}{15}  

d)

3 115\frac{1}{15}  

24.

2/5 =

a)

25%

b)

0.40

c)

40%

d)

0.25

25.

How is 145% expressed as a decimal?

a)

14.5

b)

1.45

c)

0.145

d)

14,500

26.

Which pair of numbers are NOT equivalent?

a)

0.4 and 2/5

b)

0.6 and 60%

c)

0.15 and 15/10

d)

750% and 75/10

27.

What is 0.222222... as a fraction?

a)

29\frac{2}{9}  

b)

299\frac{2}{99}  

c)

15\frac{1}{5}  

d)

19\frac{1}{9}  

e)

2299\frac{22}{99}  

28.

What is 0.181818... as a fraction?

a)

211\frac{2}{11}  

b)

950\frac{9}{50}  

c)

18110\frac{181}{10}  

d)

1999\frac{19}{99}  

e)

181999\frac{181}{999}  

29.

What is 0.757575... as a fraction?

a)

2533\frac{25}{33}  

b)

757999\frac{757}{999}  

c)

34\frac{3}{4}  

d)

56\frac{5}{6}  

e)

79\frac{7}{9}  

30.

What kind of fraction is 425What\ kind\ of\ fraction\ is\ \frac{4}{25}  

a)

Terminating

b)

Recurring

31.

Change the following recurring decimal into a fraction.


Simplify your answer if possible.

a)

143/333

b)

431/999

c)

47/111

d)

142/333

32.

Change from an ordinary number to standard form: 12,000,000

a)
12.0  x  107
b)
0.12  x  107
c)
1.2  x  106
d)
1.2  x  107
33.

Change from an ordinary number to standard form:  0.000398

a)
39.8  x  10-5
b)
3.98  x  10-5
c)
3.98  x  10-4
d)
39.8  x  10-6
34.

Change from an ordinary number to standard form:  0.000398

a)
39.8  x  10-5
b)
3.98  x  10-5
c)
3.98  x  10-4
d)
39.8  x  10-6
35.

Change from an ordinary number to standard form:  0.000398

a)
39.8  x  10-5
b)
3.98  x  10-5
c)
3.98  x  10-4
d)
39.8  x  10-6
36.

Write in standard form: 0.00071363

a)
7.1363 x 10-3
b)
7.1363 x 10-4
c)
7.1363 x 104
d)
7.1363 x 103
37.

Write the following number in standard form.

942.1×108942.1\times10^8  

a)

9.421×1089.421\times10^8  

b)

9.421×1059.421\times10^5  

c)

9.421×10119.421\times10^{11}  

d)

9.421×10109.421\times10^{10}  

38.

How would you write -5.6 x 10-3 as an ordinary number?

a)
0.0056
b)
-5,600
c)
0.00056
d)
-0.0056
39.

How do you write 8.317 x 106 as an ordinary number?

a)
8, 371, 000
b)
83, 170, 000
c)
837, 100
d)
8, 317, 000
40.

7.82 x 10-6 is an example of standard form. The power of -6 tells you your number will be very ________.

a)
Large
b)
Small
c)
Basic
41.

Give the sum in standard form.

(2.6 x 106) + (4.2 x 106)

a)

6.8 x 106

b)

6.8 x 1012

c)

8.4 x 106

d)

3.2 x 1012

42.

Give the difference in standard form.

(9.87 x 107) - (7.42 x 107)

a)

2.45 x 100

b)

3.5 x 107

c)

2.45 x 107

d)

17.29 x 107

43.

Give the difference in standard form.

(8.7 x 109) - (2.5 x 107)

a)

6.2 x 102

b)

6.2 x 109

c)

7.23 x 107

d)

8.675 x 109

44.

Divide. Give the answer in standard form.

(3 x 10-5)/(4 x 102)

a)

7.5 x 10-3

b)

7.5 x 10-8

c)

.75 x 10-7

d)

 7.0 x 102

45.

Give the sum of (9.54 x 108) + (3.22 x107) in standard form

a)

1.276 x 107

b)

8.62 x 1015

c)

12.76 x 108

d)

9.862 x 108

46.

The population of City A is 8.59×1048.59\times10^4  . The population of City B is 3.2×1033.2\times10^3  . What value shows the difference in population of City A and City B?

a)

8.27×1048.27\times10^4  

b)

5.39×1015.39\times10^1  

c)

2.748×1072.748\times10^7  

47.

Expand 7(a+4)7\left(a+4\right)  

(a)  

48.

Expand (x+2)(x+3)\left(x+2\right)\left(x+3\right)  

a)

x2+6x+5x^2+6x+5  

b)

x2+5x+6x^2+5x+6  

c)

2x+5x+62x+5x+6  

d)

x2−5x+6x^2-5x+6  

49.

Expand (x+3)2\left(x+3\right)^2  

a)

x2+3x^2+3  

b)

x2+9x^2+9  

c)

x2+6x+9x^2+6x+9  

d)

x2−6x+9x^2-6x+9  

50.

Expand (p+6)(p−3)\left(p+6\right)\left(p-3\right)  

a)

p2+3p −18p^2+3p\ -18  

b)

p2−3p−18p^2-3p-18  

c)

p2+3p +3p^2+3p\ +3  

d)

p2−18p^2-18  

51.

Write an expression for the area of the shape

a)

2m2+6m+42m^2+6m+4  

b)

m2+6m+4m^2+6m+4  

c)

2m2+6m−42m^2+6m-4  

d)

2m2−6m+42m^2-6m+4  

52.
Which of the following is the correct expansion of:
3p(4p - 7q)?
a)
7p - 10pq
b)
12pq - 21q2
c)
9q
d)
12p2 - 21pq
53.

The factorisation of 6x + 12y is :-

a)

6(x+2y)

b)

2(3x+12y)

c)

3(x+4y)

d)

none of these

54.

How does expansion work when there are two brackets?

a)

Every term in the first bracket will be subtracted with every term in the second and third bracket.

b)

Every term in the first bracket will be multiplied with every term in the second bracket.

c)

Use BODMAS.

d)

Adding of one or two expressions in brackets.

55.

Expanding brackets: 2x(8x2+6x)

a)

16x3+12x2

b)

16x2+12X

c)

16x+12x

d)

16+12

56.

Factorise: x2-5x

a)

x(x-5)

b)

x(x-5x)

c)

(x-5x)2

d)

x(5-5)

57.
Factorise 3x²+12x
a)
3x(x+4)
b)
3(x²+4)
58.

Division is the inverse process of ________________________

a)

addition

b)

subtraction

c)

multiplication

d)

division

59.

) The process of finding two or more expressions whose product is the given expression is called _____________________________

a)

polynomial

b)

algebraic expression

c)

factorisation

d)

identity

60.

The factors of 9x – 18x2 are __________________

a)

9(x – 2x)

b)

9x(1 – 2x)

c)

-9x

d)

9x(1 – 3x)

61.
(x − 3)(x − 6) =
a)
x2 − 3x + 18
b)
x2 − 6x + 12
c)
x2 − 9x − 19
d)
x2 − 9x + 18
62.

x2 - 9

a)

(x + 3)2

b)

(x + 3) (x - 3)

c)

(x - 3)2

d)

x + 3(x - 3)

63.

5x + y = 4x, To make y the subject of the equation

the first step is:

a)

subtract 5x

b)

subtract y

c)

multiply by 5

d)

divide by 5

64.

3n = 2x + 6g, To make g the subject of the equation

the first step is:

a)

subtract 3n

b)

divide by 2

c)

subtract 2x

d)

divide by 3

65.

7x + 7y = 20, to make y the subject of the equation

the first step is:

a)

subtract 7y

b)

subtract 20

c)

divide by 20

d)

subtract 7x

66.

9n + w = 1

Make w the subject of the equation.

a)

w = 9n + 1

b)

w = 10n

c)

w = -9n + 1

d)

-9n = w + 1

67.

2a + 5y = 24, make a the subject of the equation.

a)

a = (24 - 5y)/2

b)

a = (5y + 24)/2

c)

a = 5y - 24

d)

a = 2(5y + 24)

68.

Make t the subject of the equation D= rt

a)
D/r = t
b)
Dr = t
c)
D/t = r
d)
Dt = r
69.

Make h the subject of the equation

V=πr2hV=πr²h  

a)

Vπr2=h\frac{V}{πr²}=h  

b)

V−πr2=hV-πr²=h  

c)

V+πr2=hV+πr²=h  

d)

Vπ=h\frac{V}{π}=h  

70.

2a + 5y = 24, make a the subject of the equation

a)

a = (24 - 5y)/2

b)

a = (5y + 24)/2

c)

a = 5y - 24

d)

a = 2(5y + 24)

71.
Solve for t.
D= rt
a)
D/r = t
b)
Dr = t
c)
D/t = r
d)
Dt = r
72.

Solve:

V=πr2hV=πr²h  , for h

a)

Vπr2=h\frac{V}{πr²}=h  

b)

V−πr2=hV-πr²=h  

c)

V+πr2=hV+πr²=h  

d)

Vπ=h\frac{V}{π}=h  

73.

Make x the subject of the equation:

a)
x = yb - v
b)
x = by - v
c)
x = by + v
74.
What is the Rule for this sequence?
97, 86, 75, 64, ...
a)
+8
b)
+11
c)
-11
d)
-8
75.
What are the next 2 terms:
1/3, 2/3, 1, 4/3...
a)
2 and 7/3
b)
5/3 and 2
c)
5/3 and 7/3
d)
none of the above
76.

Find the nth term of the following sequence...


5, 9, 13, 17...

a)

4n+1

b)

4n-1

c)

n+4

d)

n-4

77.

Find the nth term of the following sequence...


8, 13, 18, 23...

a)

5n+3

b)

3n+5

c)

n+5

d)

n+3

78.

Find the nth term of the following sequence...


7, 16, 25, 24...

a)

9n-2

b)

9n+2

c)

9n-3

d)

9n+3

79.
Is the sequence -432, 72, -12, 2,...geometric?
a)
yes
b)
no