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WorksheetsFunction file
Total questions: 25
Worksheet time: 25mins
f(x)=x3−3x2+5
The integer function of the function are
3x2−6x
3x2−6x+C
4x4−x3+5x+C
Tıˊnh∫sinx dx
Cosx + C
- Cosx + C
- Sinx + C
Sinx + C
Ha~y Tính ∫3x1dx
3.ln (x) + C
3ln(x)+C
3ln(x)
3ln∣x∣+C
Tıˊnh∫e2xdx
2.e2x+C
2e2x+2021+C
2ex+C
−2e2x+C
Tıˊnh∫2021xdx
2021x+C
ln(2021)2021x+C
2021xln(2021)+C
ln∣2021x∣+C
The integer function of function f(x)=3x2+1 is
3x2+x+C
x3+x+C
x3+x−2
integer function of function f(x)=sinx−2cosx is?
F(x)=sinx+cosx+C
F(x)=cosx+2sinx+C
F(x)=−cosx−2sinx+C
F(x)=cosx+2sinx+C
Hàm số nguyên f(x)=sin2x2−2x is?
F(x)=2cotx+x2+C
F(x)=−2cotx+x2+C
F(x)=−2cotx−x2+C
Khẳng định nào sau đây là sai ?
∫lnx dx=x1+C.
∫cosx dx=sinx+C.
∫dx=x+C.
∫ex dx=ex+C.
A integer of function f(x)=3x2−4x+3 is number of function
F(x)=x3−2x2+3x−4.
F(x)=3x3−2x2+3x+1.
F(x)=x3−4x2+3x−9.
F(x)=6x−4.
Results of ∫2x−3dx is
21ln∣2x−3∣+C.
ln∣2x−3∣+C.
31ln∣2x−3∣+C.
−31ln∣2x−3∣+C.
Hàm số dưới đây là một hàm nguyên của số hàm f(x)=e4x−3 ?
y=41e4x−3+10.
y=e4x−3.
y=4e4x−3+9.
y=−31e4x−3−3.
With a>0 , a=1 ta có
Nguyên function ∫axdx bằng
ax.lna+C
ax+C
Hàm số nguyên
f(x)=4x−32 is
41ln∣4x−3∣+C
21ln2x−23+C
2ln∣4x−3∣+C
2ln2x−23+C
Mệnh đề nào sau đây sai?
∫exdx=ex+C
If
∫f(x)dx=4x3+x2+C thì number function f(x) bằngf(x)=x4+3x3+Cx
f(x)=12x2+2x
f(x)=x4+3x3+C
f(x)=12x2+2x+C
Tính
∫(2x+x2)dxI=31x3−4x+C
I=−31x3−4x+C
F(x)=mx3+(3m+2n)x2+2x−3
is a integer of function of function
f(x)=3x2+10x+2 . Tính mn value2
3
4
f(x)=3x−2
A number of function is
32(3x+2)(3x+2)+C
31(3x+2)(3x+2)+C
∫x(x2+2)10dx is
112(x2+2)11+C
22(x2+2)11+C
11(x2+2)11+C
22(x2+2)11+C
f(x)=x1+x31 has an integer of they
lnx+x44+C
lnx+2x21+C
ln∣x∣−2x21+C
ln∣x∣−x43+C
∫sinx+2cosxdx is
ln(sinx+2)+C
−ln∣sinx+2∣+C
ln(cosx+2)+C
−ln∣cosx+2∣+C
∫ x+13x2+2x+1dx is
23x2+x+ln∣x+1∣+C
23x2−x−2ln∣x+1∣+C
23x2−2x+ln∣x+1∣+C
23x2−x+2ln∣x+1∣+C
∫(sinx+xlnx)dx
−cosx+lnx+C
−cosx+2x2lnx+4x2+C
−cosx+2x2lnx−4x2+C
−cosx+lnx+x2+C
f(x)=4x(1+lnx) the integer of function are
2x2lnx+3x2
2x2lnx+x2
2x2lnx+3x2+C
2x2lnx+x2+C
