wayground logo

Free Printable Worksheets

Font size

S
M
L
XL
Worksheets

Compton Effect

Total questions: 10

Worksheet time: 5mins

Name
Class
Date
1.

What is Compton shift?

a)

shift in radiation

b)

shift in wavelength

c)

shift in charge

d)

shift in frequency

2.

Compton effect experiment is carried out with

a)

x ray

b)

gama ray

c)

visible light

d)

heat waves

3.

Compton scattering establishes

a)

photonic nature of electromagnetic wave

b)

wave nature of electromagnetic wave

c)

both wave and particle nature of electro magnetic

d)

electron is a matter

4.

Elements of low atomic mass are preferred in Compton effect

a)

low atomic mass elements are easily available

b)

with low atomic mass coulombic attaraction is less and greater probability of making electron free

c)

with low atomic mass coulombic attaraction is high and greater probability of making electron free

d)

with low atomic mass coulombic attaraction is less and lesser probability of making electron free

5.

In Compton effect we use X-ray because

a)

it is easy to produce

b)

it has very small wave length

c)

x-ray photon has very high energy

d)

it is a X-ray diffraction experiment

6.

Compton wave length is

a)

hm0C\frac{h}{m0C}

b)

hmc\frac{h}{mc}

c)

hλC\frac{h}{\lambda C}

d)

(1Cosα)\left(1-Cos\alpha\right)

7.

Compton Shift given by Δλ=λc(1Cosα)\Delta\lambda=\lambda c\left(1-Cos\alpha\right)  becomes maximum at

a)

scattering angle equal to 90 degree

b)

scattering angle equal to 0 degree

c)

scattering angle equal to 180 degree

d)

scattering angle equal to 360 degree

8.

We do not use heavy atoms in Compton effect study because

a)

in heavy atom electron-nuclear coulombic attraction is very strong

b)

in heavy atom electron-nuclear coulombic attraction is very weak

c)

in heavy atom electron-electron coulombic attraction is very strong

d)

in heavy atom electron-visible light interaction is very weak

9.

The expression for Compton shift is

a)

hm0ccosθ\frac{h}{m_0c}\cos\theta  

b)

hm0csinθ\frac{h}{m_0c}\sin\theta  

c)

hm0c(1cosθ)\frac{h}{m_0c}\left(1-\cos\theta\right)  

d)

hm0c(1sinθ)\frac{h}{m_0c}\left(1-\sin\theta\right)  

10.

The Compton effect can be explained on the basis of __________

a)

Ray optics

b)

Wave optics

c)

Quantum theory of light

d)

Wave nature of light