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WorksheetsMathematical Induction
Total questions: 64
Worksheet time: 53mins
What is the third step in Mathematical induction?
P(1)
P(k+1)
P(k)
n=k
1 + 3 + 5 + 7 + . . . + (2n − 1) = n2
On the basis of this assumption, [The statement is true for n = k:
1 + 3 + 5 + 7 + . . . + (2k − 1) = k2]
What must we show next?
The statement is true for n = 1:
(2)(1) − 1 = 12
The statement is true for n = k:
1 + 3 + 5 + 7 + . . . + (2k − 1) = k2
The statement is true for n = k + 1:
1 + 3 + 5 + 7 + . . . + (2k − 1) + (2k + 1) = (k + 1)2
Let P(n) = 2n − 1. Evaluate:
a) P(k)
b) P(k + 1)
a) P(k) = 2k − 1
b) P(k + 1) = 2n + 1
a) P(k) = 2k + 1
b) P(k + 1) = 2(k + 1) - 1
a) P(k) = 2k − 1
b) P(k + 1) = 2k + 1
1 + 3 + 5 + 7 + . . . + (2n − 1) = n2
To prove this by mathematical induction, what will be the induction assumption?
The statement is true for n = k:
1 + 3 + 5 + 7 + . . . + (2k − 1) = k2
The statement is true for n = 1:
(2)(1) − 1 = 12
The statement is true for n = k + 1:
1 + 3 + 5 + 7 + . . . + (2k − 1) + (2k + 1) = (k + 1)2
What is the first step in Mathematical Induction?
P(k)
n=k
P(k+1)
P(1)
On the basis of this assumption,
[The statement is true for n = k:
1 + 3 + 5 + 7 + . . . + (2k − 1) = k2]
What must we show?
2x1 − 1 = 12
1 + 3 + 5 + 7 + . . . + (2k − 1) = k2
1 + 3 + 5 + 7 + . . . + (2k − 1) + (2k + 1) = (k + 1)2
a) S(k)
b) S(k + 1)
b) S(k + 1) = 2n + 1
b) S(k + 1) = 2k + 1
b) S(k + 1) = 2k + 1
1 + 3 + 5 + 7 + . . . + (2n − 1) = n2
On the basis of this assumption,
[The statement is true for n = k:
1 + 3 + 5 + 7 + . . . + (2k − 1) = k2]
What must we show next?
The statement is true for n = 1:
2x1 − 1 = 12
The statement is true for n = k:
1 + 3 + 5 + 7 + . . . + (2k − 1) = k2
The statement is true for n = k + 1:
1 + 3 + 5 + 7 + . . . + (2k − 1) + (2k + 1) = (k + 1)2
When using mathematical induction to prove : i=1∑ni2=6n(n+1)(2n+1) . In step #2, after you have made your assumption, what are you trying to prove? (What is your goal?)
i=1∑k+1i2=6(k)(k+1)(2k+1)+(k+1)2
Sk+1=6k(k+1)(2k+1)
i=1∑k+1i2=6(k+1)(k+2)(2k+3)
Sk+1=(k+1)2
What does the principle of mathematical induciton state
if the base case (for n = 1) is true and inductive step is true, then the theorem holds for all positive integers
if the base case (for n = 1) is true and inductive step is false, then the theorem holds for all positive integers
if the base case (for n = 1) is false and inductive step is true, then the theorem holds for all positive integers
if the base case (for n = 1) is false and inductive step is false, then the theorem holds for all positive integers
What value of n will satisfy the base case?
0
1
2
3
Find the coefficient of x3 in...
(2 + x)5
40
10
20
80
Find the coefficient of x4 in...
(3 + x)6
135
15
45
540
Find the coefficient of x3 in...
(1 - x)7
-35
35
-21
21
Find the coefficient of x2 in...
(2 - x)6
240
-240
30
-30
Find the coefficient of x3 in...
(1 + 3x)5
270
90
30
810
Find the coefficient of x2 in...
(1 + 2x)6
60
30
15
120
Find the coefficient of x3 in...
(1 - 5x)4
-500
500
100
-100
Find the coefficient of x2 in...
(3 - 2x)4
216
-219
432
-432
Evaluate 21C1
21
1
2
32
Choose the right Pascal's triangle
Consider the binomial expansion of (2y−5x)6 . How many terms are there in the expansion?
6
5
7
4
Use the binomial expansion to expand (u2−2)3
u6−6u4+12u2−8
u6−16u4+12u2−8
5u6−20u4+40u2−40
u6−24u4+12u2−8
Use the binomial theorem to expand (4−2z)3
64−96z+48z2+8z3
64−96z+48z2−8z3
64+96z+48z2+8z3
64−64z+144z2−8z3
What is the first term of (2r−s)8
64r
64r8
256r8
128r8
Using (2y−5x)6 , find the third term of the expansion.
6000x4y2
6000x3y5
6000x2y4
6001x2y4
From (x2−2y)7 , find the fifth term.
566x6y4
550x6y5
560x6y4
560x4y6
Consider the binomial expansion of (3x2−2y3)5 . Find the third term of the expansion.
1080x6y6
1180x4y5
1088x6y4
1011x6y6
Given (3x−32y2)5 . Use Binomial Theorem to find the fourth term of the expansion.
−380x2y6
−380x2y4
−380x2y2
−388x2y6
Find the coefficient of the term x8y3 of (3x2−2y3)5
-811
-800
-810
-910
Find the coefficient of x5 in the expansion of (2−x)(3x+1)9
91854
88547
11238
51030
83×82×81×80×79 can also be written as:
78!83!
79!83!
8378!
8378
True or False...
40,500 is divisible by 6
True
False
Which of the following is NOT divisible by 4?
1,000
5,740
1,566
2,024
All of these numbers are divisible by 5 except...
1050
155
980
2938
Is 2,385 divisible by 10?
Yes
No
105 is NOT divisible by which of the following numbers?
1
5
3
2
Which of these numbers is divisible by 2 AND 5?
675
674
670
673
55 is divisible by what number?
5
2
10
6
543 is divisible by which of the following? Select all that apply.
5
8
10
3
1
684,933 is divisible by which of the following numbers? (select all that apply)
3
5
7
8
9
What is the divisibility rule for 4?
The last two digits form a number divisible by 4
The last digit is a number divisible by 4
The last digit is even
The last digit is zero
What is the divisibility rule for 5?
It is divisible by 2 and 3
The last digit is a five
The last digit is five or zero
The last digit is zero
Which of the following statements is true of this number?
It is divisible by 3 and 9
It is divisible by 2, 3, and 6
It is divisible by 3
It is prime
Which of the following statements is true of this number?
It is divisible by 2, 6, and 9
It is divisible by 3 and 9
It is divisible by 3
It is prime
What is the divisibility rule of 9?
The sum of the digits is a number divisible by 3
The sum of the digits is a number divisible by 9
The last two digits form a number divisible by 3
The last digit is zero
Is 1,284,604 divisible by 2?
Yes, because the sum of the digits is 20, which is an even number
No, because 4 is an odd number
Yes, because 4 is an even number
No, because the it is not divisible by 3
2520 is divisible by 6 because:
It is divisible by 2 (even) and 5 (ends in a 0 or 5)
The sum of the digits is 12, a multiple of 6
It's divisible by 2 (even) and 3 (sum of digits is a multiple of 3)
The sum of the digits is even
How do you know if a number is divisible by 12?
The sum of the digits must be a multiple of 12
If it ends in 3, 6, or 9
If it is divisible by 3 and 4
If it is divisible by 2 or 3
Is 81 divisible by 3?
Yes, because the sum of the digits is 9, a multiple of 3
No, because 81 is an odd number
Yes, because 81 is an odd number
No, because 81 does not end in 3
Is 36,928 divisible by 4?
Yes, because the sum of the digits is a multiple of 4
Yes, because it is an even number
Yes because the last two digits, 28, is divisible by 4
Yes, because it is divisible by 2 and 3
Is 19,584 divisible by 9?
Yes
No
60__2
54,322 is divisible by 3
True
False
What is the divisibility rule for 1
It has to be an even number
Every number is divisible by 1
Add up all of the digits and if it is divisible by 1 then the whole number is.
Is 61 Prime or Composite?
Prime
Composite
insert the greatest digit to make the following number divisible by 3.
98732_6
9
8
7
1
insert the correct digit to make the following number divisible by 9.
987654_2
6
4
13
1
