WorksheetsNewton's Laws, Torque & UG Review
Total questions: 14
Worksheet time: 15mins
Inertia
Newtons 1st Law
F=MA
Newton's 2nd LawF=MA
Equal and Opposite Forces Interacting
Newton's 3rd Law
The attracted force between two objects
Universal Gravitation
r2Gm1m2 or
m*g
Fg=
Reorder the following steps to solve for this word problem:
Two asteroids that have masses of 1.8 x 10^9 kg and 9.2 x 10^16 kg. Their centers are separated by a distance of 2500 m. Find the gravitational force between them.
M1 = 1.8E9 Kg
M2 =9.2E16 Kg
r =1000 m
G =6.67E-11
Fg=r2Gm1m2
Fg= (10002(6.67E−11)(1.8E9)(9.2E16))
1E61.10E16
1.1E10N
Kg
Mass
m
Radius
N
Force
s2m
Acceleration
Nm
Torque
Two identical asteroids are initially at rest when the gravitational attraction between the two asteroids causes them to move.
How will their motion happen?
They will accelerate towards each other at a constant rate the whole time
They will accelerate towards each other at an increasing rate every moment.
They will slow down their motion as they get closer to one another.
They will move at a constant velocity towards each other.
Which object will have the highest gravity?
Earth
Moon
Venus
Jupiter
Force
X-Axis
Acceleration
Y-Axis
AF
mass=
3 s2m
When F=0.75N,
A=?
Remember in math: What you do to one side of the equation, you do to the other.
With F=MA,
If you double the Force, what will happen to the acceleration?
The acceleration will double
The acceleration will be halved
The acceleration will be tripled
The acceleration will not change.
Match the following to work through calculating the acceleration of this 1500 kg vehicle.
(Ff) + (Fgp)
(-8000) + (2000 )
Fx(net)
M*A
Fnet=
MassF(net)
A=
1500 kg
Mass
-6000N
Fx (net)
Reorder the following process to determine how much friction is applied to this 50 kg box accelerating at 5 s2m .
m= 50 kg
a = 5 s2m
Fx(net) =?
Fx(net)=ma
F(net) =50*5
Fx(net) = 250N
F(net)=Ff + Fp
Ff=F(net) - Fp
Ff=F(net) - Fp
Ff= 250-700
Ff=-450N
T=Fr
Which labeled givens will result with the highest torque.
F=1
r=2
F=2
r=2
F=1
r=1
F=1
r=2
Reorder the following to solve how much torque this wrench has. The radius from the center to the end is 0.10m with 20N of force.
F= 20N
r= 0.10m
T=?
T=Fr
T=20*0.10
T=2Nm
Reorder the following to solve how much Force this engine's pistons have. The engine's crankshaft has a length of 0.75m from the pivot point. It creates approximately 100Nm of Torque.
T=100 Nm
r= 0.75m
F=?
T=Fr therefore...
F=rT
F=100/0.75
F=133.3N
If this box is traveling at a constant 20 m/s towards you from this screen, will its motion be changed after these forces are applied?
yes
no
This box is traveling at a constant 20 m/s from this screen towards you when these forces are applied?
What is the new motion of the box?
it is at rest
it accelerates towards you.
it accelerates to the right
It remains moving at the constant 20 m/s velocity.
