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Exponential Test Review 2

Total questions: 65

Worksheet time: 2hrs 33mins

Name
Class
Date
1.

If the decay rate is 20%, which of the following represent the decay factor?

a)

0.2

b)

0.8

c)

1.2

d)

1.8

2.

If the decay rate is 20%, which of the following represent the decay factor?

a)

0.2

b)

0.8

c)

1.2

d)

1.8

3.

If the growth rate is 80%, what is the growth factor?

a)

0.2

b)

0.8

c)

1.2

d)

1.8

4.

 A flea medicine breaks down at a rate of 20% per hour.  This is the rate of decay of the medicine. The initial dose is 60 milligrams. Which of the following represent the equation the models the amount of flea medicine left in an animal?

a)

y=60(.2)xy=60\left(.2\right)^x  

b)

y=20(60)xy=20\left(60\right)^x  

c)

y=60(.8)xy=60\left(.8\right)^x  

d)

y=60(1.2)xy=60\left(1.2\right)^x  

5.

Jack invest $600 earning 5% interest rate. How much will he have after 5 years?

a)

$630

b)

$729.30

c)

$765.77

d)

$4556.25

6.
A population of fish starts at 8,000 and decreases by 6% per year. What is the population of fish after 10 years?
a)
14327
b)
4309
c)
839
d)
7680
7.

Classify the model as Exponential GROWTH.  

a)

Growth  y=a(1+r)ty=a\left(1+r\right)^t  

b)

Decay  y=a(1−r)ty=a\left(1-r\right)^t  

8.

What is the formula for exponential growth?

a)

y=a(1+r)ty=a\left(1+r\right)^t  

b)

y=a(1−r)ty=a\left(1-r\right)^t  

c)

y=a(1+rt)y=a\left(1+rt\right)  

d)

y=a(a−rt)y=a\left(a-rt\right)  

9.

What is the formula for exponential decay?

a)

y=a(1+r)ty=a\left(1+r\right)^t  

b)

y=a(1−r)ty=a\left(1-r\right)^t  

c)

y=a(1+rt)y=a\left(1+rt\right)  

d)

y=a(a−rt)y=a\left(a-rt\right)  

10.

What does "a" stand for in the exponential growth formula?

y=a(1+r)ty=a\left(1+r\right)^t  

a)

final amount

b)

time

c)

original amount

d)

rate of growth

11.

What does "r" stand for in the exponential growth formula?

y=a(1+r)ty=a\left(1+r\right)^t  

a)

final amount

b)

time

c)

original amount

d)

rate of growth

12.

What does "t" stand for in the exponential growth formula?

y=a(1+r)ty=a\left(1+r\right)^t  

a)

final amount

b)

time

c)

original amount

d)

rate of growth

13.

What does "y" stand for in the exponential growth formula?

y=a(1+r)ty=a\left(1+r\right)^t  

a)

final amount

b)

time

c)

original amount

d)

rate of growth

14.

Marburn has 80 total students in our High School. It is projected to grow at rate of 2% every year. How many students will be in the High School in 5 years from now?

a)

72.3 students

b)

88.3 students

c)

199.1 students

d)

80 students

15.

The population of a town is decreasing at a rate of 5% per year. This year there are 10,000 people in this town, how many people will be left in 20 years from now? (round to the nearest whole number)

a)

26,533 people

b)

358 people

c)

1 person

d)

3,585 people

16.

Growth or Decay?

y=1200(1+0.03)ty=1200\left(1+0.03\right)^t  

a)

Growth

b)

Decay

17.

What is the original amount?

y=1200(1+0.03)ty=1200\left(1+0.03\right)^t  

a)

Growth

b)

1200

c)

0.03

d)

Decay

18.

What is the rate of growth?

y=1200(1+0.03)ty=1200\left(1+0.03\right)^t  

a)

Growth

b)

1200

c)

0.03

d)

Decay

19.

Growth or Decay?

y=55(1−0.02)ty=55\left(1-0.02\right)^t  

a)

Growth

b)

Decay

20.

What is the original amount?

y=55(1−0.02)ty=55\left(1-0.02\right)^t  

a)

Growth

b)

Decay

c)

55

d)

0.02

21.

What is the decay rate?

y=55(1−0.02)ty=55\left(1-0.02\right)^t  

a)

Growth

b)

Decay

c)

55

d)

0.02

22.
A population of fish starts at 8,000 and decreases by 6% per year. What is the population of fish after 10 years?
a)
14327
b)
4309
c)
839
d)
7680
23.
Daniel’s Print Shop purchased a new printer for $35,000. Each year it depreciates at a rate of 5%. How much will the printer be worth in 8 years?
a)
$23,219.72
b)
$136.72
c)
$51,710.94
d)
$16,710.94
24.
The number of mosquitoes at the beginning of the summer was 4,000. The population of mosquitoes is expected to grow at a rate of 25% a month. How many mosquitoes will there be after 4 months?
a)
9766
b)
9006
c)
9765
d)
5433
25.
Twenty years ago, Mr. Davis purchased his home for $160,000. Since then, the value of the home has increased about 5% per year. How much is the home worth today?
a)
$176,783.29
b)
$424,527.63
c)
$57,357.75
d)
$532,041,076.80
26.
The original value of a painting is $1400, and the value increases by 9% each year. Write an exponential growth function to model this situation.
a)
y=1400(1.09)x
b)
y=1.09(1400)x
c)
y=1400(.91)x
d)
y=1.09x
27.
Which of the following functions shows an initial amount of $15 and an increase of 35% each year?
a)
y = 15(35)x
b)
y = 15(1.35)x
c)
y = 15(0.35)x
d)
y = 35(1.15)x
28.

Florine-21 has a half-life of 4 seconds. You begin with a 50 mg sample of Florine-21.


Write an exponential equation to represent the amount of Florine-21, f(t), in mg, after t seconds.

a)

f(t)=50(2)t4f\left(t\right)=50\left(2\right)^{\frac{t}{4}}

b)

f(t)=50(12)4tf\left(t\right)=50\left(\frac{1}{2}\right)^{4t}

c)

f(t)=50(12)t64f\left(t\right)=50\left(\frac{1}{2}\right)^{\frac{t}{64}}

d)

f(t)=50(12)t4f\left(t\right)=50\left(\frac{1}{2}\right)^{\frac{t}{4}}

29.

How much would you need to deposit into an account that pays 6.5% interest compounded semiannually to have $10,000 after 7 years?

a)

$7012.49

b)

$4615.28

c)

$5930.18

d)

$6390.59

30.

A group of yeast cells doubles every 4 hours. There is a population of 100 cells.

Write an exponential equation to represent the number of yeast cells Y(t), after t hours. 

a)

Y(t)=100(12)t4Y\left(t\right)=100\left(\frac{1}{2}\right)^{\frac{t}{4}}  

b)

Y(t)=100(2)4tY\left(t\right)=100\left(2\right)^{4t}  

c)

Y(t)=100(2)t4Y\left(t\right)=100\left(2\right)^{\frac{t}{4}}  

d)

Y(t)=2(100)t4Y\left(t\right)=2\left(100\right)^{\frac{t}{4}}  

31.

Florine-21 has a half-life of 4 seconds. You begin with a 50 mg sample of Florine-21.


Write an exponential equation to represent the amount of Florine-21, f(t), in mg, after t seconds.

a)

f(t)=50(2)t4f\left(t\right)=50\left(2\right)^{\frac{t}{4}}

b)

f(t)=50(12)4tf\left(t\right)=50\left(\frac{1}{2}\right)^{4t}

c)

f(t)=50(12)t64f\left(t\right)=50\left(\frac{1}{2}\right)^{\frac{t}{64}}

d)

f(t)=50(12)t4f\left(t\right)=50\left(\frac{1}{2}\right)^{\frac{t}{4}}

32.

A certain car loses half of its value every 5 years.


If the value of the car after 8 years is $12,450, what was the initial value of the car?

a)

$24,900

b)

$19,920

c)

$37,741

d)

$4,107

33.

Bob wants to buy a car. The one he wants costs $12,500. If he has $3000 and deposits it into an account that pays 7.5% compounded monthly, how long will it be before he can buy the car?

a)

14.04 years

b)

19.08 years

c)

22.41 years

d)

11.13 years

34.

How much would you need to deposit into an account that pays 6.5% interest compounded semiannually to have $10,000 after 7 years?

a)

$7012.49

b)

$4615.28

c)

$5930.18

d)

$6390.59

35.

Katy deposited $90 in a savings account earning 5% interest, compounded quarterly. Which of the following equations could represent the amount of money in her account yearly?

a)
b)
c)
d)
36.

Derrick has $1,000 in a savings account that ears 15% interest, compounded monthly. To the nearest cent, how much will he have in 2 years?

a)

$5,350.25

b)

$1,322.50

c)

$1,025.16

d)

$1,347.35

37.

You have 30,016 grams of radioactive kind of rubidium. How much will be left after 54 minutes if its half-life is 18 minutes?

a)

15,008 grams.

b)

7,504 grams

c)

3,752 grams.

d)

1,876 grams.

38.

What does the n stand for in this formula?

a)

Initial amount

b)

Final amount

c)

Rate

d)

Time

e)

The number of times compounded per year

39.
If 10 mg of iodine 131 is given to a patient, how much is left after 24 days? The half-life of iodine-131 is 8 days.
a)
1.25mg
b)
1.25g
c)
10g
d)
10mg
40.

If you deposit $8,000 into an account paying 7% annual interest compounded quarterly, how long until there is $12,400 in the account?

a)

7.3 yrs

b)

6.5 yrs

c)

5.6 yrs

d)

6 yrs

41.

Katy deposited $90 in a savings account earning 5% interest, compounded quarterly. Which of the following equations could represent the amount of money in her account yearly?

a)
b)
c)
d)
42.

The simple interest formula is I=PRT.  What does the T represent?

a)

Principal

b)

Time, in hours

c)

Interest

d)

Time, in years

43.

Write 0.37 as a percent (%)

a)

37%

b)

.37%

c)

3.7%

44.

Write 4.3% as a decimal.

a)

4.3

b)

.43

c)

0.043

d)

4300

45.

What does the "I" in the interest formula stand for?

a)

Principal

b)

Rate

c)

Time

d)

Interest

46.

What does the "R" in the interest formula stand for?

a)

Rate

b)

Principal

c)

Interest

d)

Time

47.

Dan borrows $1200 from a bank with 8% simple interest per year.  How much will he have to pay back IN TOTAL after 2 years?

a)

$150

b)

$1350

c)

$192

d)

$1392

48.

The rate is given as a percent (%).  Before using it in the simple interest formula, you must first convert it to a______.

a)

Fraction

b)

Decimal

c)

Ratio

d)

Dollar Amount

49.

Question #1

If you wish to calculate the amount of interest earned on an investment with a rate of 6.17%, what number will you plug into your equation for the rate?

A. 0.00617

B. 0.0617

C. 0.617

D. 6.17

a)

A

b)

B

c)

C

d)

D

50.
What is the formula for simple interest?
a)
A=P(1+r)t
b)
I=Prt
c)
I=P(1+r)t
d)
A=Prt
51.

What does the P in I =PRT mean?

a)

Power

b)

Principal

c)

Product

d)

Percent

52.
The Principal and Interest are always___________.
a)
fraction
b)
decimal
c)
percent
d)
money
53.
Write the decimal as a percent. 
0.37
a)
37%
b)
3.7%
c)
.37%
54.

Find the interest

p= $34,100

r = 4%

t = 3 years

a)

4092

b)

40920

c)

4324

d)

3254

55.

Rachel invested $2,700 in a savings account earning 7% simple interest. If she invests for 2 years, how much money will she have in TOTAL?

(Interest + principal)

a)

$3,078

b)

$378

c)

$40,500

d)

$4536

56.
Maria borrowed $3,000 at a simple interest rate of 4% per year.  How much did she have to repay after 4 years?
a)

$3480

b)
$3,480
c)
$4,800
d)
$7,800
57.
Starting money = $350.
Interest rate = 2.5%
TIme = 3 years.
How much interest?
a)
$7.50
b)
$26.25
c)
$87.5
d)
$262.50
58.

Find the balance in the account after the given period.

$12,000 principal earing 4.8% compounded annually after 7 years.

a)

$3,243.19

b)

$16,661.35

c)

$15,243.19

d)

$4,661.35

59.

Find the balance in the account after the given period.

$13,500 deposit earning 3.3% compounded monthly after 1 year

a)

$13,611.38

b)

$14,898.84

c)

$13,537.13

d)

$13, 952.30

60.

Find the balance in the account after the given period.

$3400 principal earning 3.6% compounded annually after 2 years

a)

$3,420.43

b)

$3,649.21

c)

$3,675.39

d)

$6,288.64

61.

Change 25% to decimal

a)

.25

b)

2.5

c)

25

d)

25.

62.

Change 20% to decimal

a)

2.00

b)

.20

c)

2.0

d)

0.02

63.

Change 1% to decimal

a)

.1

b)

00.1

c)

.01

d)

1.0

64.

Convert 7.2% to a decimal.

a)

72

b)

720

c)

0.072

d)

0.0072

65.
2% as a decimal:
a)
0.02
b)
0.2
c)
2
d)
20