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Total questions: 76
Worksheet time: 11hrs 24mins
Given the differential equation dP/Dt=5P
A) Find the general solution for P to the differential equation
B)Find the particular solution for P to the differential equation given P(0)= 418
A) P=Ce5t
B) P= 5e418t
A) P=Ce5t
B) P= 418e5t
A) P=Cet
B) P= 418et
A) P=Ce10t
B) P= 418e10t
The population of the little town of Scorpion Gulch is now 1000 people. The population is presently growing at about 5% per year.
Find the general solution.
P=.05e1000t
P=1000e5t
P=1000e.05t
p=lne1000t
Y is proportional to the difference of x and z
y= x-z
y= k(z-x)
y= k(x-z)
y= z-x
dy/dx = 2x/e2y find the general solution
y = ln (2x/2 + C)
2
y = ln(2x/2)+c
y = e2x+c
y = mx+b
2. Solve the differential equation
𝑑𝑦/𝑑𝑡 =3𝑡2/𝑦 with initial condition
𝑦(2) = 0.
𝑦 = ln(15t)
𝑦 = 16t3
𝑦 = (2𝑡3 − 16)1/2
𝑦 = (2𝑡3 −16)
dy/dx= x √y
Find the general solution
√y = ln|4x| + c
√y = (x)-1 + c
2y1/2 = ln|x| + c
1/2y1/2 = ln|x| + c
y varies jointly with x and the square of z
y= kxz2
y= kx√z
y= kxz
kx2z
what would the sign of the square root after finding c be given the initial condition g(1)= -5
positive
negative
Dy/dx= tanx+15x2+ex+1/x
y= -ln|sinx| + 5x3 + ex + ln|x| + c
y= secxtanx + 5x3 + ex + ln|x| + c
y= -ln|cosx| + 5x3 + ex + ln|x| + c
y= sec2(x) + 5x3 + ex + ln|x| + c
dp/dy = (4y)-1find the general solution
p= 1/5y5/4 + c
p= 1/4ln|4y| + c
p= 1/8y2 + c
p= 1 + c
4y
y is proportional to the product of z and the square root of x
y= z(x2)
y= kz(x2)
y= kx√z
y=zkx
dy/dx = 4x/y. Suppose y(0)=1
The particular solution is
B
C
D
E
Find the particular solution for y if dy/dx = 2x√y and y = 4 when x = 3.
2√y = x2 + C
y = (x2 + 25)2/4
y = (x2/2-5/2)1/2
y = x4/4
State what type of variation the equation represents.
Direct
Inverse
Joint
None
State what type of variation the equation represents.
Direct
Inverse
Joint
None
If x varies inversely as v, and x = 35 when v = 3, find x when v = 15.
7
9
5
21
y = 400/x
If x=2,y=27; when x=6,y=9; find y when x =3
9
18
3
27
x is directly proportional to y,but inversely proportional to z. x=⅙, for y=5 and z=9, find x when y=6 & z =⅕.
9
3y/10z
6
5
T varies directly as the square root of p and inversely as the square of g. This joint variation can be written as
T∝pg
T∝gp
T∝gp
T∝g2p
The relations between variables T,w,x is T∝wx2 . It is given that T=32 when x=4 and w=6. Express T in terms of w and x.
w12x2
w3x2
12wx2
w24x2
Given that m∝p and m= 10 and p=4. Find the value of p if m= 35.
7
9
49
81
Given that y∝(x+2)n1 and y=21 when n = 2 and x = 2. Find the value of n when y = 1 and x = 6
81
21
1
2
Given S varies inversely as the square of T and S = 36 when T=21 . Express S in terms of T.
S=T29
S=T236
S=T236
S=T272
Table 1 shows the value of p, q and r.
Given that p∝2rp , calulate the value of m
1
2
4
8
t = 20 when p = 4 and r = 2.
Find t when r = 10 and p = -5.
The relationship between variables K, L and M is shown in the equation KL2 = M . State the relationship of K, L and M in words.
K varies directly as square of L and inversely ad square root of M
K varies directly as square root of M and inversely as square of L
K varies directly as square of M and inversely as square root of L
K varies directly as square root of L and inversely as square of M
Table 1 shows the value of p, q and r.
Given that p∝2rp , calulate the value of m
1
2
4
8
If y = 22.5 when x = 15, find y when x = 20.
t = 20 when p = 4 and r = 2.
Find t when r = 10 and p = -5.
a2 + b2 + c2
a2 + b2 + c2
