WorksheetsInternal Viva Voce ACL EC7L02
Total questions: 14
Worksheet time: 44mins
Name
Class
Date
1.
The name Minimum Shift Keying (MSK) implies
a)
the minimum frequency separation that allows orthogonal detection as two FSK signals VH(t) & VL(t).
b)
the maximum frequency separation that allows orthogonal detection as two FSK signals VH(t) & VL(t).
c)
the minimum frequency separation that allows non orthogonal detection as two FSK signals VH(t) & VL(t).
d)
the maximum frequency separation that allows non orthogonal detection as two FSK signals VH(t) & VL(t).
2.
Select the MSK properties which makes the modulation is efficient
a)
constant envelope
b)
Spectral efficiency
c)
Good BER performance
d)
Self-synchronizing capability
3.
The phase of the signal is shown in below figure. With the help of this figure find the data being sent is ____.
a)
111010000
b)
000010111
c)
000011101
d)
110011001
4.
What is the bandwidth efficiency for the 64-QAM using bit transmission speed of 512 KHz?
a)
6
b)
3
c)
4
d)
5
5.
A bit stream 1101011011 is transmitted using the standard CRC method. The generator polynomial is X^4+X+1. What is the actual bit string transmitted?
a)
11010110111110
b)
11010110111111
c)
11010110111100
d)
11010110111011
6.
Check whether receiver detect any error for the bit stream received by the receiver is 10111101100. (Assume generator polynomial sequence is 1001)
a)
there is an error because remainder is non zero value “100”
b)
there is an error because remainder is non zero value “101”
c)
there is no error because remainder is zero value “000”
d)
there is no error because remainder is non zero value “110”
7.
The impulse response of the Gaussian filter is:
a)
Option 1
b)
Option 2
c)
Option 3
d)
Option 4
8.
What is the value for BT (Bandwidth-Time) product for GMSK and GFSK?
a)
BT=0.3 for GMSK and BT=0.5 for GFSK
b)
BT=0.5 for GMSK and BT=0.3 for GFSK
c)
BT=0.8 for GMSK and BT=0.7 for GFSK
d)
BT=0.7 for GMSK and BT=0.8 for GFSK
9.
To achieve a data rate of 256 Kbps using GFSK, the -3dB cutoff bandwidth is
a)
128 KHz
b)
256KHz
c)
76.8 KHz
d)
204.8 KHz
10.
At what value of the BT (Bandwidth-Time) Product GMSK is equivalent to MSK
a)
Infinity
b)
Zero
c)
One
d)
1/2
11.
Select the True statements which belongs to Gaussian Filter characteristics
a)
Narrow bandwidth and sharp cutoff to suppress high frequency components
b)
Small overshoot impulse response to prevent excess deviation of the instantaneous frequency
c)
Narrow bandwidth and sharp cutoff to suppress Low frequency components
d)
Large overshoot impulse response to prevent excess deviation of the instantaneous frequency
12.
Statement: The frequency difference between the logical one and logical zero states is always equal to half the data rate. The above mentioned statement is suits for which modulation.
a)
GMSK
b)
GFSK
c)
FSK
d)
MSK
13.
Choose the Modulation from the below frequency response.
a)
A: MSK, B: GFSK, C: GMSK
b)
B: MSK, A: GFSK, C: GMSK
c)
A: MSK, C: GFSK, B: GMSK
d)
C: MSK, B: GFSK, A: GMSK
14.
In the DCL kit, we are using 32 KHz PRBS clock frequency to generate an data sequence. When we press the start button counter starts counting the error bits till it’s time (maximum time limit for the counter is 30 seconds). After 30 seconds, BER error counter shows the value of “ACE” (Hexagonal Form). Find the BER Ratio.
a)
0.00288
b)
0.0288
c)
0.0057625
d)
0.05762
100 %
