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Coulomb's Law

Total questions: 9

Worksheet time: 13mins

Name
Class
Date
1.

Which of the following charges will attract each other?

a)

-4 μC & -5 μC

b)

4 μC & 5 μC

c)

4 C & 5 C

d)

-4 μC & 5 μC

2.

What does the "q" represent in Coulomb's Law?

a)

quarks

b)

quantum

c)

charge

d)

coulomb's constant

3.

What does the "d" represent in Coulomb's Law?

a)

radius of the electron

b)

distance between charges

c)

radius of the proton

d)

distance a charge will travel

4.

What is the value of Coulomb's Constant (k)?

a)

8.99 x 109 Nm2C-2

b)

8.987 Nm2C-2

c)

8.987 x 1011 Nm2C-2

d)

7.1 x 104.5 Nm2C-2

5.

A balloon with a charge of 6.25×109C-6.25\times10^{-9}C is held at a distance of 0.617 m from a second balloon having the same charge. Identify the value of distance (d) that would be used to solve Coulomb's Law.

a)

0.617 m

b)

6.25×109C-6.25\times10^{-9}C

c)

9.0×109 Nm2C29.0\times10^9\ \frac{N\cdot m^2}{C^2}

d)

6.25×109C6.25\times10^{-9}C

6.

When distance increases, the electrostatic force between the particles ​ (a)   . We call this a(n) ​ (b)   proportional relationship

Choose from the below words

decreases

indirectly

increases

directly

7.

A balloon with a charge of 6.25×109C-6.25\times10^{-9}C is held at a distance of 0.617 m from a second balloon having the same charge. Identify the value of q1 that would be used to solve Coulomb's Law.

a)

0.617 m

b)

6.25×109C-6.25\times10^{-9}C

c)

9 x 103 N

d)

6.25×109C6.25\times10^{-9}C

8.

A balloon with a charge of 6.25×109C-6.25\times10^{-9}C is held at a distance of 0.617 m from a second balloon having the same charge. Identify the value of k that would be used to solve Coulomb's Law.

a)

0.617 m

b)

6.25×109C-6.25\times10^{-9}C

c)

8.99×109 Nm2C28.99\times10^9\ \frac{N\cdot m^2}{C^2}

d)

6.25×109C6.25\times10^{-9}C

9.

A balloon with a charge of 6.25×109C-6.25\times10^{-9}C is held at a distance of 0.617 m from a second balloon having the same charge. What is the value of the force between the two particles? (Hint: Solve Coulomb's Law!)

a)

9.22×107N9.22\times10^{-7}N

b)

6.25×109C-6.25\times10^{-9}C

c)

9.0×109 Nm2C29.0\times10^9\ \frac{N\cdot m^2}{C^2}

d)

6.25×109C6.25\times10^{-9}C