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Simplifica:
23x3y2 ⋅ 34x2y\frac{2}{3}x^3y^2\ \cdot\ \frac{3}{4}x^2y32x3y2 ⋅ 43x2y
12x5y3\frac{1}{2}x^5y^321x5y3
612x5y\frac{6}{12}x^5y126x5y
36x5y3\frac{3}{6}x^5y^363x5y3
12x5y2\frac{1}{2}x^5y^221x5y2
(4x4+2x2)÷2x2=\left(4x^4+2x^2\right)\div2x^2=(4x4+2x2)÷2x2=
2x2+12x^2+12x2+1
2x22x^22x2
Resolver: 5x+z−4x−3z+2y5x+z-4x-3z+2y5x+z−4x−3z+2y
−x+2y+4z-x+2y+4z−x+2y+4z
x+2y+2zx+2y+2zx+2y+2z
x−2y−2zx-2y-2zx−2y−2z
x+2y−2zx+2y-2zx+2y−2z
Descontar 2000 al precio de un saco de arroz.
x - 2000
2000 - x
2000(x - 2000)
x/2000
Valor numérico x3 −2x2 −3x +2 para x=2x^{3\ }-2x^{2\ }-3x\ +2\ \ \ para\ \ \ x=2x3 −2x2 −3x +2 para x=2
121212
888
−4-4−4
−8-8−8
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